y (-2,4) (2, 4) 3+ (-1,1) (1,1) + -4 -i(0, 0) -3 2 3 4 -2+ 6. 4. 2.

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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## Parabolic Function Graph Explanation

### Graph Description

This graph represents a parabolic function, which is a type of quadratic function. The graph is plotted on a Cartesian coordinate system with the x-axis (horizontal) and y-axis (vertical). 

### Key Points on the Graph

The graph includes several key points marked and labeled:
- The vertex of the parabola is at the origin, denoted as (0,0).
- The graph passes through points (−1,1) and (1,1), which provide symmetry about the y-axis.
- Additional points on the parabola include (−2,4) and (2,4), indicating the function's value at these x-coordinates.

### Parabola Properties

- **Symmetry:** This parabola is symmetric about the y-axis. This can be seen as for every point (x, y) on one side of the y-axis, there is a corresponding point (−x, y) on the opposite side.
- **Vertex:** The vertex at (0,0) is the lowest point on the graph, indicating that the parabola opens upwards.
- **Direction:** The parabolic arms open upwards, which suggests that the quadratic term \( ax^2 \) has a positive coefficient.

### Interactive Feature

At the bottom of the graph image, there is an interactive feature indicating a target submission:
- "0/5 targets" which likely signifies an interactive exercise where users need to identify or interact with certain points on the parabola.
- A "Submit" button is present, which can be used to finalize user input regarding the targets.

In summary, this graph is a visual representation of a quadratic function, specifically a simple parabola with its vertex at the origin and various symmetric points across the y-axis. The interactive aspect at the bottom invites learners to engage with the graph further.
Transcribed Image Text:## Parabolic Function Graph Explanation ### Graph Description This graph represents a parabolic function, which is a type of quadratic function. The graph is plotted on a Cartesian coordinate system with the x-axis (horizontal) and y-axis (vertical). ### Key Points on the Graph The graph includes several key points marked and labeled: - The vertex of the parabola is at the origin, denoted as (0,0). - The graph passes through points (−1,1) and (1,1), which provide symmetry about the y-axis. - Additional points on the parabola include (−2,4) and (2,4), indicating the function's value at these x-coordinates. ### Parabola Properties - **Symmetry:** This parabola is symmetric about the y-axis. This can be seen as for every point (x, y) on one side of the y-axis, there is a corresponding point (−x, y) on the opposite side. - **Vertex:** The vertex at (0,0) is the lowest point on the graph, indicating that the parabola opens upwards. - **Direction:** The parabolic arms open upwards, which suggests that the quadratic term \( ax^2 \) has a positive coefficient. ### Interactive Feature At the bottom of the graph image, there is an interactive feature indicating a target submission: - "0/5 targets" which likely signifies an interactive exercise where users need to identify or interact with certain points on the parabola. - A "Submit" button is present, which can be used to finalize user input regarding the targets. In summary, this graph is a visual representation of a quadratic function, specifically a simple parabola with its vertex at the origin and various symmetric points across the y-axis. The interactive aspect at the bottom invites learners to engage with the graph further.
**The graph of \( f(x) = x^2 \) is shown below with five specific points labeled. Plot the location of each of these five points after the graph is reflected vertically.**

In this task, you are presented with a quadratic function \( f(x) = x^2 \). The graph of this function is a parabola that opens upwards. The current graph has five points that are labeled for reference.

After reflecting this graph vertically, each y-coordinate of the labeled points will be transformed. If a point on the original graph is at coordinates (x, y), reflecting it vertically will result in a new point at (x, -y).

**Steps to complete the task:**

1. Identify the coordinates of the five labeled points on the original graph.
2. Reflect each point vertically by changing the sign of the y-coordinate.
3. Plot the new set of points on the graph accordingly.

**Example:**

If one of the labeled points on the original graph is (2, 4):
- The y-coordinate is 4.
- After vertical reflection, the new y-coordinate will be -4.
- So, the new point will be (2, -4).

Apply this process to all five labeled points to complete the reflection.
Transcribed Image Text:**The graph of \( f(x) = x^2 \) is shown below with five specific points labeled. Plot the location of each of these five points after the graph is reflected vertically.** In this task, you are presented with a quadratic function \( f(x) = x^2 \). The graph of this function is a parabola that opens upwards. The current graph has five points that are labeled for reference. After reflecting this graph vertically, each y-coordinate of the labeled points will be transformed. If a point on the original graph is at coordinates (x, y), reflecting it vertically will result in a new point at (x, -y). **Steps to complete the task:** 1. Identify the coordinates of the five labeled points on the original graph. 2. Reflect each point vertically by changing the sign of the y-coordinate. 3. Plot the new set of points on the graph accordingly. **Example:** If one of the labeled points on the original graph is (2, 4): - The y-coordinate is 4. - After vertical reflection, the new y-coordinate will be -4. - So, the new point will be (2, -4). Apply this process to all five labeled points to complete the reflection.
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