y = −0.05t + 47 (0 ≤ t ≤ 60), where y is the temperature of the CPU in degrees Celsius and t is the number of seconds into the experiment.
y = −0.05t + 47 (0 ≤ t ≤ 60), where y is the temperature of the CPU in degrees Celsius and t is the number of seconds into the experiment.
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Question
A hardware engineer is looking at the temperature of Central Processing
Units (CPUs) of different computers. In one experiment, the
temperature of the CPU of her own computer can be modelled by the
equation
y = −0.05t + 47 (0 ≤ t ≤ 60),
where y is the temperature of the CPU in degrees Celsius and t is the
number of seconds into the experiment.
Transcribed Image Text:(b) The same engineer decides to look into rates of cooling for liquids to
experiment with different cooling solutions for servers. She finds that
the rate of cooling for one liquid can be modelled by the equation:
y = 48 x 0.99*
where y is the temperature of the liquid in degrees Celsius and t is the
(0 <t < 80)
time in minutes.
(i) State whether the type of reduction for this model is linear or
exponential. Describe how reduction rate differs between linear and
exponential functions.
(ii) Calculate the temperature when t = 20.
(iii) Write down the scale factor and use this to find the percentage
decrease in the temperature per minute.
(iv) Use the method shown in Subsection 5.2 of Unit 13 to find the time
at which the temperature is 30°.
(v) Determine the halving time of the temperature.
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