X~ NOrmaly distributed mean=ll=d00 Standard deviation=o= 26 zニ X-l X

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Please explain how you got 1.469

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X~ NOTmally
distributed
mean=ll=200
Standard deviation=o = 26
Z= Xall
given P( x<x) = 0.9.9
= 0.१२१
here we tind x=
Step 2
given
P(x<x) = 0.929
%31
here we find x = ?
P( X-ll c x-200
26
0१২৭
T
Transcribed Image Text:1:34 AA A bartleby.com = bartleby E Q&A Math / Statistics / Q&A Library / Let x be a continuous rando... Let x be a continuous random variable tha... Get live help whenever you Try bartleby tutor today need from online tutors! X~ NOTmally distributed mean=ll=200 Standard deviation=o = 26 Z= Xall given P( x<x) = 0.9.9 = 0.१२१ here we tind x= Step 2 given P(x<x) = 0.929 %31 here we find x = ? P( X-ll c x-200 26 0१২৭ T
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Let x be a continuous random variable tha...
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Step 2
given
P(x<x)
= 0.१२१
here we find x= 1
P(
X-l cx- 200
26
= 0.929
%3D
z < x-Q0
P(Z< X-200
26
p (Z<
= 0.929
→ P(z<i469)= D•929
X- 200
%3D
l.469
26
X= 200+|1469 x26)
X a 238.18
>
T
Transcribed Image Text:1:34 AA A bartleby.com = bartleby E Q&A Math / Statistics / Q&A Library / Let x be a continuous rando... Let x be a continuous random variable tha... Get live help whenever you Try bartleby tutor today need from online tutors! Step 2 given P(x<x) = 0.१२१ here we find x= 1 P( X-l cx- 200 26 = 0.929 %3D z < x-Q0 P(Z< X-200 26 p (Z< = 0.929 → P(z<i469)= D•929 X- 200 %3D l.469 26 X= 200+|1469 x26) X a 238.18 > T
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