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xyz f(x,y,z) 이000 0010 0101 0110 1001 1011 1100 1111 O f(x, y, z) = xyz + xyz + xyz + xyz O f(x, y, z) = xyz + xyz + xyz + xyz O f(x, y, z) = xyz + xyz O None of the above

xyz f(x,y,z) 이000 0010 0101 0110 1001 1011 1100 1111 O f(x, y, z) = xyz + xyz + xyz + xyz O f(x, y, z) = xyz + xyz + xyz + xyz O f(x, y, z) = xyz + xyz O None of the above

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The image presents a truth table for a Boolean function f(x, y, z) and provides multiple-choice options for expressing this function in standard form. ### Truth Table | x | y | z | f(x, y, z) | |---|---|---|-----------| | 0 | 0 | 0 | 0 | | 0 | 0 | 1 | 0 | | 0 | 1 | 0 | 1 | | 0 | 1 | 1 | 0 | | 1 | 0 | 0 | 1 | | 1 | 0 | 1 | 1 | | 1 | 1 | 0 | 0 | | 1 | 1 | 1 | 1 | ### Multiple-Choice Options 1. \( f(x, y, z) = \overline{x}yz + xy\overline{z} + x\overline{y}z + xyz \) 2. \( f(x, y, z) = xyz + xy\overline{z} + x\overline{y}z + xyz \) 3. \( f(x, y, z) = \overline{x}yz + xy\overline{z} \) 4. None of the above This setup is typically used to find the correct Boolean expression that matches the given truth table.
Transcribed Image Text:The image presents a truth table for a Boolean function f(x, y, z) and provides multiple-choice options for expressing this function in standard form. ### Truth Table | x | y | z | f(x, y, z) | |---|---|---|-----------| | 0 | 0 | 0 | 0 | | 0 | 0 | 1 | 0 | | 0 | 1 | 0 | 1 | | 0 | 1 | 1 | 0 | | 1 | 0 | 0 | 1 | | 1 | 0 | 1 | 1 | | 1 | 1 | 0 | 0 | | 1 | 1 | 1 | 1 | ### Multiple-Choice Options 1. \( f(x, y, z) = \overline{x}yz + xy\overline{z} + x\overline{y}z + xyz \) 2. \( f(x, y, z) = xyz + xy\overline{z} + x\overline{y}z + xyz \) 3. \( f(x, y, z) = \overline{x}yz + xy\overline{z} \) 4. None of the above This setup is typically used to find the correct Boolean expression that matches the given truth table.
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