xy' + ky + 5etk+1 = 0 for x > 0. Here, k is an arbitrary positive constant and g(x) is a continuous function for all x ER. Then, the most general solution is given by, khere C is an arbitrary constant: A) y = ex*+ C (B)y = ex+C (C) none of these (D)y = Ce (E)y = Cx*-et* F) y = et* + Cx*

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider
xy' + ky + 5e4xk+1 _ 0
for x > 0. Here, k is an arbitrary positive constant and g(x) is a continuous function for all x ER. Then, the most
general solution is given by, kshere Cis an arbitrary constant:
A) y = ex+ C (B)y = ex+C (C) none of these (D)y = Ce (E)y = Cx* -et*
F)y = et* + Cx*
Transcribed Image Text:Consider xy' + ky + 5e4xk+1 _ 0 for x > 0. Here, k is an arbitrary positive constant and g(x) is a continuous function for all x ER. Then, the most general solution is given by, kshere Cis an arbitrary constant: A) y = ex+ C (B)y = ex+C (C) none of these (D)y = Ce (E)y = Cx* -et* F)y = et* + Cx*
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