x(t) = 7sin (20rt) cos (200at)) The Fourier transform of the given signal is X(f) = (4)(8(f – 90) + 8 (f + 110) – 8 (f – 110) – 8 (f + 90)) The numerical values of the constants are A =| and B=

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**Required Information**

Consider the following signals.

\[ x(t) = 7\sin (20\pi t) \cos (200\pi t) \]

The Fourier transform of the given signal is

\[ 
X(f) = \left(\frac{jA}{B}\right) \left( \delta(f - 90) + \delta(f + 110) - \delta(f - 110) - \delta(f + 90) \right)
\]

The numerical values of the constants are \( A = \_\_\_\_\_ \) and \( B = \_\_\_\_\_ \).
Transcribed Image Text:**Required Information** Consider the following signals. \[ x(t) = 7\sin (20\pi t) \cos (200\pi t) \] The Fourier transform of the given signal is \[ X(f) = \left(\frac{jA}{B}\right) \left( \delta(f - 90) + \delta(f + 110) - \delta(f - 110) - \delta(f + 90) \right) \] The numerical values of the constants are \( A = \_\_\_\_\_ \) and \( B = \_\_\_\_\_ \).
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