explain what each line of code is doing from the picture below.This instruction looks as if it loads r7 with the contents of memory location P1. Recall that ARM processors don’t support such an addressing mode. This instruction is a pseudoinstruction that will be assembled into suitable ARM code. (please no copy and paste from articles) AREA Directives, CODE, READONLYENTRY;load r6 with 5 (i.e., XX);load r7 with the contents of location P1²'just a dummy instruction;angel_SWIreason_ReportException;ADP_Stopped_ApplicationExit;ARM semihosting (formerly SWI);equate XX to 5;store hex 32-bit value 1345678store the byte 25 in memorystore byte whose ASCII character is A in memorystore the 16-bit value 12342 in memoryensure code is on a 32-bit word boundaryMOVr6, #XXLDRr7,P1ADDr5,r6,r7ro, #0x18rl, =0x20026svCMOVLDR#0x123456XXEQU5P1DCD0x12345678P3DCB25YYDCB'A'Тx2DCW12342ALIGNStrgl ="Hello"Strg2"X2", &0С, &0AZ3DCWОХАВСDEND

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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explain what each line of code is doing from the picture below.

This instruction looks as if it loads r7 with the contents of memory location P1. Recall that ARM processors don’t support such an addressing mode. This instruction is a pseudoinstruction that will be assembled into suitable ARM code.

(please no copy and paste from articles)

AREA Directives, CODE, READONLY
ENTRY
;load r6 with 5 (i.e., XX)
;load r7 with the contents of location P1²'
just a dummy instruction
;angel_SWIreason_ReportException
;ADP_Stopped_ApplicationExit
;ARM semihosting (formerly SWI)
;equate XX to 5
;store hex 32-bit value 1345678
store the byte 25 in memory
store byte whose ASCII character is A in memory
store the 16-bit value 12342 in memory
ensure code is on a 32-bit word boundary
MOV
r6, #XX
LDR
r7,P1
ADD
r5,r6,r7
ro, #0x18
rl, =0x20026
svC
MOV
LDR
#0x123456
XX
EQU
5
P1
DCD
0x12345678
P3
DCB
25
YY
DCB
'A'
Тx2
DCW
12342
ALIGN
Strgl =
"Hello"
Strg2
"X2", &0С, &0A
Z3
DCW
ОХАВСD
END

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