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- ● S/2 | sin(t) |dt •(3+27) de dx - (18) The acceleration function in km/sec² is a(t) 3t+7 where time t is in seconds, and 0 ≤t≤ 10. Let v(t) (in km/sec) and s(t) (in km) be the velocity and position functions = 4 km. = 45 km/sec and the initial position s(0) respectively with the initial velocity, v(0) Find the velocity function and the position functions. Then, find the total distance covered.The function s(t) describes the motion of a particle along a line s(t)= t^2_18t+24 a) identify the time intervals in which the particles is moving in a negative directionThe velocity function (in meters per second) is given for a particle moving along a line. v(t) = t - 4t – 12, 1 sts 8 %3D (a) Find the displacement. m (b) Find the distance traveled by the particle during the given time interval. m
- The position of a particle in millimeters is given by s = 112 - 23t+t² where t is in seconds. Plot the s-t and v-t relationships for the first 16 seconds. Determine the net displacement As during that interval and the total distance D traveled. By inspection of the s-t relationship, what conclusion can you reach regarding the acceleration?What is the convertion to the average velocity ( mm / s )