xample -19 -1.6 X10C2. What is the electric charge le 14 in MC of 5x 10 protons 21
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1p = 1.6 X10C2. What is the electric charge in MC of 5x10" protons
21
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- Please answer the following question(s): 1. Electron Proton Calculate the potential energy of an electron and proton in a hydrogen atom (use J): -19 leV = 1.6 x 10-1 In Joules: J In eV: eV -19 Use that the magnitude charge on an electron and a proton is 1.6X101°C, the atomic radius is 5.3x10 1'm, and k=9 ×10° Nm?/C?. -11An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.0400g droplet hovers motionless when the electric field is set to 370N/C and directed downward. a. What was the charge of the oil droplet in Coulombs? b. Determine the approximate number of excess or defecit electrons on the droplet.Q1) A point charge 100 pc is located at (4, 1 ,-3) while the x-axis carries charge 2 nc/m. If the plane z=3 also carries charge 5 nc/m², find E at (1,1,1). Q2) Find the electric field intensity at (0,0,5) caused by each of the following charge distributions in free space: Ring:- pL = 5 nc /m , r= 8, z=0. Disc:- ps = 2 nc/m2, 014. A completely ionized atom (net charge +Q) is accelerated through a potential difference V. What is the increase in kinetic energy of the atom?The charge moving between the plates has magnitude |q| = 10 µC. The voltage between the plates is 15 V, and the electric field between the capacitor plates is 70 N/C. How far apart are the plates? a. 4.67 m b. 0.214 m c. 6000.00 m d. 1050 m3. In electrostatics if the electric field is vanished at a point, then the electric potential must be also vanished at this point. A.(True) B.(Fale)charge to mass ratio 7or elęctrons is 9lme=1:76x1o"C|Kg, and tor protons it is q/mp-9.57X10c}kg. na715 the ratIO 07 The Proon 's masi To+ne ejectron's? mplme=? %3D2. The resting concentration of calcium ions, Ca (valence Z=2 for calcium), is about Cin = 10-3 mole/liter in the extracellular space but is very low (Cout =10 mole/liter) inside muscle cells. Determine the membrane potential AV for calcium. Suppose diffusion temperature T = 27 °C.What will happen if two protons close to each other were released from rest? A. They will attract B. They will move in opposite directions and stop C. They will move in opposite directions and continue moving forever. D. They will move towards each other and stop. a O b2c) Considering electron and proton as two charged particles separated by d = 5 × 10-11 m calculate the following: i) the electrostatic potential at a distance d from the proton. ii) the potential energy of the electron in the field of the proton iii) the Coulomb force between proton and electron iv) the gravitational force between the proton and electron and find its ratio to the Coulomb force. Take the mass of the proton 1.7 x 10-27 kg, the mass of the electron 9.1 x 10-31 kg, the electron charge -1.6 x 10-19 C, the value of the universal gravitational constant 1 6.7 × 10-11 N kg-2m-2 and Απο 9 x 10° m/F.1. An electron is to be accelerated in a uniform electric field having a strength of 2.1-106 (a) What energy in keV is given to the electron if it is accelerated through 0.3 m? AKE = keV m (b) Over what distance (in km) would it have to be accelerated to increase its energy by 43 GeV? d = km Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is the potential difference, V, related to the uniform electric field?SEE MORE QUESTIONS