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XA possible solution uses an if statement for user_num1, and an if-else statement for user_num2. 1: Compare output a File "main.py", line 8 if user_num2 => 11 SyntaxError: invalid syntax Output differs. See highlights below. Input 12 X Your output Expected output user_num2 is 3 2: Compare output a File "main.py", line 8 if user_num2 => 11 SyntaxError: invalid syntax Output differs. See highlights below.

XA possible solution uses an if statement for user_num1, and an if-else statement for user_num2. 1: Compare output a File "main.py", line 8 if user_num2 => 11 SyntaxError: invalid syntax Output differs. See highlights below. Input 12 X Your output Expected output user_num2 is 3 2: Compare output a File "main.py", line 8 if user_num2 => 11 SyntaxError: invalid syntax Output differs. See highlights below.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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4.7.2: If-else statements.
 
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Print "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 3 if user_num2 is greater than 11. Otherwise, print "user_num2 is less than or equal to 11.". End with newline.
 
 
A possible solution uses an if statement for `user_num1`, and an if-else statement for `user_num2`. 1. **Compare output 1:** - **Error Message:** ``` File "main.py", line 8 if user_num2 => 11 ^ SyntaxError: invalid syntax ``` - **Details:** The output differs from the expected result. The code attempts to use `=>` for comparison, which results in a syntax error. The correct operator for comparison should be `>=`. - **Input:** ``` 0 12 ``` - **Output:** Your output is not present. The expected output is: ``` user_num2 is 3 ``` 2. **Compare output 2:** - **Error Message:** ``` File "main.py", line 8 if user_num2 => 11 ^ SyntaxError: invalid syntax ``` - **Details:** Similar to the first comparison, there is a syntax error due to the incorrect use of the `=>` operator. The code does not execute properly and the output is not as expected. - **Note:** This example highlights the importance of using correct syntax in programming, especially when using conditional statements. Using the wrong operators can lead to errors and prevent code from running.
Transcribed Image Text:A possible solution uses an if statement for `user_num1`, and an if-else statement for `user_num2`. 1. **Compare output 1:** - **Error Message:** ``` File "main.py", line 8 if user_num2 => 11 ^ SyntaxError: invalid syntax ``` - **Details:** The output differs from the expected result. The code attempts to use `=>` for comparison, which results in a syntax error. The correct operator for comparison should be `>=`. - **Input:** ``` 0 12 ``` - **Output:** Your output is not present. The expected output is: ``` user_num2 is 3 ``` 2. **Compare output 2:** - **Error Message:** ``` File "main.py", line 8 if user_num2 => 11 ^ SyntaxError: invalid syntax ``` - **Details:** Similar to the first comparison, there is a syntax error due to the incorrect use of the `=>` operator. The code does not execute properly and the output is not as expected. - **Note:** This example highlights the importance of using correct syntax in programming, especially when using conditional statements. Using the wrong operators can lead to errors and prevent code from running.
```python user_num1 = int(input()) user_num2 = int(input()) if user_num1 < 0: print('user_num1 is negative') if user_num2 <= 11: print('user_num2 is less than or equal to 11.') print('user_num2 is', user_num2) ``` ### Explanation: This code snippet is designed to take two integer inputs from the user and perform checks based on their values. - **Lines 1-2**: The code reads two integers from the input and assigns them to `user_num1` and `user_num2`. - **Line 4**: It checks if `user_num1` is less than 0. If true, it prints that `user_num1` is negative. - **Line 7**: It checks if `user_num2` is less than or equal to 11. If true, it prints that `user_num2` is less than or equal to 11. - **Line 10**: Finally, it prints the value of `user_num2`. ### Interface Elements: - **"Check" Button**: Likely used to verify if the input meets certain criteria or if the code behaves as expected. - **"Try again" Button**: Allows the user to modify inputs or retry the operation, possibly after a failed check. (Note: There appears to be a small error in the code on line 7. The operator `=>` should be `<=` to correctly check if `user_num2` is less than or equal to 11.)
Transcribed Image Text:```python user_num1 = int(input()) user_num2 = int(input()) if user_num1 < 0: print('user_num1 is negative') if user_num2 <= 11: print('user_num2 is less than or equal to 11.') print('user_num2 is', user_num2) ``` ### Explanation: This code snippet is designed to take two integer inputs from the user and perform checks based on their values. - **Lines 1-2**: The code reads two integers from the input and assigns them to `user_num1` and `user_num2`. - **Line 4**: It checks if `user_num1` is less than 0. If true, it prints that `user_num1` is negative. - **Line 7**: It checks if `user_num2` is less than or equal to 11. If true, it prints that `user_num2` is less than or equal to 11. - **Line 10**: Finally, it prints the value of `user_num2`. ### Interface Elements: - **"Check" Button**: Likely used to verify if the input meets certain criteria or if the code behaves as expected. - **"Try again" Button**: Allows the user to modify inputs or retry the operation, possibly after a failed check. (Note: There appears to be a small error in the code on line 7. The operator `=>` should be `<=` to correctly check if `user_num2` is less than or equal to 11.)
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