XA 0.0 mol m³.sec. 1 m³-sec -TA -TA mol FAO (m³.sec -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction A B 0.6 Feed Flow Rate = 0.8- 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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c

(C) For two CSTRS in series where each CSTR is 1.6 m^3, determine the conversion after each reactor.
Transcribed Image Text:(C) For two CSTRS in series where each CSTR is 1.6 m^3, determine the conversion after each reactor.
XA 0.0
mol
-TA ³-sec
1 (m³-sec)
-TA mol
FAO (m³-sec
-TA
mol
0.49
0.1
0.41
0.2
0.34
0.4
0.199
Reaction A → B
0.6
0.117
mol
sec PureA
T = 500K & P = 830 kPa (8.2 atm)
Feed Flow Rate = 0.8
0.7
0.083
0.8
0.054
Transcribed Image Text:XA 0.0 mol -TA ³-sec 1 (m³-sec) -TA mol FAO (m³-sec -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction A → B 0.6 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) Feed Flow Rate = 0.8 0.7 0.083 0.8 0.054
Expert Solution
Step 1: Conversion in two CSTR in series

Given, feed flow rate

F subscript A 0 end subscript space equals space 0.8 space fraction numerator m o l over denominator s e c end fraction

Tabulating the data of fraction numerator F subscript A o end subscript over denominator negative r subscript A end fraction and XA 

XAfraction numerator F subscript A 0 end subscript over denominator negative r subscript A end fraction
X subscript A open parentheses fraction numerator F subscript A 0 end subscript over denominator negative r subscript A end fraction close parentheses
0.01.6330
0.11.9510.1951
0.22.3530.470
0.44.021.608
0.66.8344.102
0.79.6386.447
0.814.81511.852
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