XA 0.0 mol m³.sec. 1 m³-sec -TA -TA mol FAO (m³.sec -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction A B 0.6 Feed Flow Rate = 0.8- 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054
XA 0.0 mol m³.sec. 1 m³-sec -TA -TA mol FAO (m³.sec -TA mol 0.49 0.1 0.41 0.2 0.34 0.4 0.199 Reaction A B 0.6 Feed Flow Rate = 0.8- 0.117 mol sec PureA T = 500K & P = 830 kPa (8.2 atm) 0.7 0.083 0.8 0.054
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
100%
c

Transcribed Image Text:(C) For two CSTRS in series where each CSTR is 1.6 m^3, determine the conversion after each reactor.

Transcribed Image Text:XA 0.0
mol
-TA ³-sec
1 (m³-sec)
-TA mol
FAO (m³-sec
-TA
mol
0.49
0.1
0.41
0.2
0.34
0.4
0.199
Reaction A → B
0.6
0.117
mol
sec PureA
T = 500K & P = 830 kPa (8.2 atm)
Feed Flow Rate = 0.8
0.7
0.083
0.8
0.054
Expert Solution

Step 1: Conversion in two CSTR in series
Given, feed flow rate
Tabulating the data of and XA
XA | ||
0.0 | 1.633 | 0 |
0.1 | 1.951 | 0.1951 |
0.2 | 2.353 | 0.470 |
0.4 | 4.02 | 1.608 |
0.6 | 6.834 | 4.102 |
0.7 | 9.638 | 6.447 |
0.8 | 14.815 | 11.852 |
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