X50: tenRun For each multiple of 10 in the given array, change all the values following it to be that multiple of 10, until encountering another multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}. Examples: tenRun ({2, 10, 3, 4, 20, 5}) -> {2, 10, 10, 10, 20, 20} tenRun ({10, 1, 20, 2}) -> {10, 10, 20, 20} tenRun ({10, 1, 9, 20}) -> {10, 10, 10, 20} Your Answer: Feedback Your feedback will appear here when you check 1 public int[] tenRun(int[] nums) 2{ your answer. N m4 5

X50: tenRun For each multiple of 10 in the given array, change all the values following it to be that multiple of 10, until encountering another multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}. Examples: tenRun ({2, 10, 3, 4, 20, 5}) -> {2, 10, 10, 10, 20, 20} tenRun ({10, 1, 20, 2}) -> {10, 10, 20, 20} tenRun ({10, 1, 9, 20}) -> {10, 10, 10, 20} Your Answer: Feedback Your feedback will appear here when you check 1 public int[] tenRun(int[] nums) 2{ your answer. N m4 5

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Array

The simplest way to start thinking about an array is as a collection, or a set of elements. In programming, these elements may be constants, variables, functions and pointers.

Question

X50: tenRun
For each multiple of 10 in the given array, change all the values following it to be that multiple of 10, until encountering
another multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}.
Examples:
tenRun ({2, 10, 3, 4, 20, 5}) -> {2, 10, 10, 10, 20, 20}
tenRun ({10, 1, 20, 2}) -> {10, 10, 20, 20}
tenRun ({10, 1, 9, 20}) -> {10, 10, 10, 20}
Your Answer:
Feedback
Your feedback will appear here when you check
1 public int[] tenRun (int[] nums)
2 {
your answer.
3
}
5

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