x°(4x2 – 1) dx is equal to |x°(2x – 1)3 A. x5(5x + 3) + C 15

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A: To evaluate: ∫2x3−2x2−3x4+x2dx Let, I=∫2x3−2x2−3x4+x2dx ⇒I=∫2x3−2x2−3x2x2+1dx

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