x+4 if x<-2 if 23 Is it possible to defined f at x=-2 in such a way that f becomes continuous at x=-2? If so, then we should set f(-2)=_. A) yes, 2 B) yes, -2 C) nо, - Is it possible to defined f at x=1 in such a way that f becomes continuous at x=1? If so, then we should set f(1)=_. A) yes, 2 B) yes, -2 C) nо, - Is it possible to defined f at x=3 in such a way that f becomes continuous at x= 3? If so, then we should set f (3) = A) yes, 4 B) yes, -4 C) nо, -
x+4 if x<-2 if 23 Is it possible to defined f at x=-2 in such a way that f becomes continuous at x=-2? If so, then we should set f(-2)=_. A) yes, 2 B) yes, -2 C) nо, - Is it possible to defined f at x=1 in such a way that f becomes continuous at x=1? If so, then we should set f(1)=_. A) yes, 2 B) yes, -2 C) nо, - Is it possible to defined f at x=3 in such a way that f becomes continuous at x= 3? If so, then we should set f (3) = A) yes, 4 B) yes, -4 C) nо, -
Chapter3: Functions
Section3.6: Absolute Value Functions
Problem 8SE: Find all function values f(x) such that the distance from f(x) to the value 8 is less than 0.03...
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can you please help me..no need to show solution
![x+4
if x<-2
if 2<x<-2
Let f (x)
|x² – 2x+1 if 1<x<3
10— 2х
if x>3
Is it possible to defined f at x=-2 in such a way that f becomes continuous
at x=-2? If so, then we should set f (-2):
A)
yes, 2
B)
yes, -2
C)
по, -
Is it possible to defined f at x=1 in such a way that f becomes continuous at
x=1? If so, then we should set f (1)=_.
-
A)
yes, 2
B)
yes, -2
C)
nо, -
Is it possible to defined f at x=3 in such a way that f becomes continuous at
x=3? If so, then we should set f (3)=
A)
yes, 4
B)
yes, -4
C)
nо, -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4b27578-becf-45e6-8799-df84a4c8a787%2F9180f3b0-40f2-4f7d-8bd5-5634b8e67dc3%2F4n66pn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:x+4
if x<-2
if 2<x<-2
Let f (x)
|x² – 2x+1 if 1<x<3
10— 2х
if x>3
Is it possible to defined f at x=-2 in such a way that f becomes continuous
at x=-2? If so, then we should set f (-2):
A)
yes, 2
B)
yes, -2
C)
по, -
Is it possible to defined f at x=1 in such a way that f becomes continuous at
x=1? If so, then we should set f (1)=_.
-
A)
yes, 2
B)
yes, -2
C)
nо, -
Is it possible to defined f at x=3 in such a way that f becomes continuous at
x=3? If so, then we should set f (3)=
A)
yes, 4
B)
yes, -4
C)
nо, -
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