x3 – 7x2 + 5x + 7 = 0, (-1, 1) Let f(x) = x3 - 7x2 + 5x + 7. f(x) is ---Select--- f(-1) = on the closed interval [-1, 1]. and f(1) = (a) (b) . Thus f(-1) and f(1) ---Select--- opposite signs. By the Existence of Zeros of a Continuous Function, there ---Select--- a number c in (-1, 1) such that f(c) = 0. Thus, there ---Select--- a solution of the equation x - 7x2 + 5x + 7 = 0 in the interval (-1, 1).

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