X(3 34. Find the surface area of a cylinder with radius 10 cm and height 13 cm. A. 1632.8 cm² B. 1583.4 cm² 2πrh+ 2πr 1445,13 C. 722.2 cm² D. 1444.4 cm² 25 Final
X(3 34. Find the surface area of a cylinder with radius 10 cm and height 13 cm. A. 1632.8 cm² B. 1583.4 cm² 2πrh+ 2πr 1445,13 C. 722.2 cm² D. 1444.4 cm² 25 Final
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
![## Educational Exercise on Geometry Concepts
### 34. Find the surface area of a cylinder with radius 10 cm and height 13 cm.
- **A. 1632.8 cm²**
- **B. 1583.4 cm²**
- **C. 722.2 cm²**
- **D. 1444.4 cm²**
Calculation:
\[ \text{Surface Area of a cylinder} = 2\pi rh + 2\pi r^2 \]
\[ r = 10 \text{ cm}, \, h = 13 \text{ cm} \]
### 35. Find the probability that a random point is within the shaded region. Express your answer as percent to the nearest tenth.
- Visual Description:
- A square with a side length of 10 units.
- A circle is inscribed within the square.
- The shaded region is outside the circle but within the square.
Possible Answers:
- **A. 78.5%**
- **B. 21.5%**
- **C. 27.3%**
- **D. 72.2%**
Visualizes the area calculation:
\[ \text{Area of square} = 10 \times 10 = 100 \text{ units²} \]
\[ \text{Radius of circle} = 5 \text{ units} \]
\[ \text{Area of circle} = \pi \times 5^2 \approx 78.5 \text{ units²} \]
\[ \text{Shaded area} = 100 - 78.5 = 21.5 \text{ units²} \]
\[ \text{Probability} = \left( \frac{21.5}{100} \right) \times 100\% = 21.5\% \]
### 36. Describe the cross section.
- **A. square**
- **B. rectangle**
- **C. triangular prism**
- **D. cube**
Visual Description:
- A three-dimensional cube is intersected in a way that produces a hexagonal cross section.
Assessment:
Given the way the cube is intersected by an oblique plane, possible option describing this situation appropriately could be visually assessed from the provided diagram.
### Practice Problem
37. Find the volume of a square pyramid with slant height 13 cm and base edge 10 cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d544791-a77c-4b5e-888b-2e8a4014205c%2Fe8fae13f-d115-4d7d-b126-dccc90407c32%2Fk03xhxj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Educational Exercise on Geometry Concepts
### 34. Find the surface area of a cylinder with radius 10 cm and height 13 cm.
- **A. 1632.8 cm²**
- **B. 1583.4 cm²**
- **C. 722.2 cm²**
- **D. 1444.4 cm²**
Calculation:
\[ \text{Surface Area of a cylinder} = 2\pi rh + 2\pi r^2 \]
\[ r = 10 \text{ cm}, \, h = 13 \text{ cm} \]
### 35. Find the probability that a random point is within the shaded region. Express your answer as percent to the nearest tenth.
- Visual Description:
- A square with a side length of 10 units.
- A circle is inscribed within the square.
- The shaded region is outside the circle but within the square.
Possible Answers:
- **A. 78.5%**
- **B. 21.5%**
- **C. 27.3%**
- **D. 72.2%**
Visualizes the area calculation:
\[ \text{Area of square} = 10 \times 10 = 100 \text{ units²} \]
\[ \text{Radius of circle} = 5 \text{ units} \]
\[ \text{Area of circle} = \pi \times 5^2 \approx 78.5 \text{ units²} \]
\[ \text{Shaded area} = 100 - 78.5 = 21.5 \text{ units²} \]
\[ \text{Probability} = \left( \frac{21.5}{100} \right) \times 100\% = 21.5\% \]
### 36. Describe the cross section.
- **A. square**
- **B. rectangle**
- **C. triangular prism**
- **D. cube**
Visual Description:
- A three-dimensional cube is intersected in a way that produces a hexagonal cross section.
Assessment:
Given the way the cube is intersected by an oblique plane, possible option describing this situation appropriately could be visually assessed from the provided diagram.
### Practice Problem
37. Find the volume of a square pyramid with slant height 13 cm and base edge 10 cm
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