x3-27 x+3x-7x+12 using direct substitution. Evaluate lim O a.) b.) c.) d.) x³-27 x+3x-7x+12 lim x³-27 x+3x-7x+12 lim algebraically by simplifying if possible, then x³-27 x+3x²-7x+12 lim x³-27 x+3x²-7x+12 lim does not exist - 27 = 27 0

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A:

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A:

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A: