X275: Recursion Programming Exercise: Check Palindrome Write a recursive function named checkPalindrome that takes a string as input, and returns true if the string is a palindrome and false if it is not a palindrome. A string is a palindrome if it reads the same forwards or backwards. Recall that str.charAt (a) will return the character at position a in str. str.substring(a) will return the substring of str from position a to the end of str, while str.substring(a, b) will return the substring of Er starting at position a and continuing to (but not including) the character at position b.

C++ Programming: From Problem Analysis to Program Design
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ISBN:9781337102087
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Chapter15: Recursion
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Code Workout
X275: Recursion Programming
Exercise: Check Palindrome
Write a recursive function named checkPalindrome that takes a string as input,
and returns true if the string is a palindrome and false if it is not a palindrome. A
string is a palindrome if it reads the same forwards or backwards.
Recall that str.charAt(a) will return the character at position a in str.
str.substring(a) will return the substring of str from position a to the end
of str,while str.substring(a, b) will return the substring of str starting
at position a and continuing to (but not including) the character at position b.
Examples:
checkPalindrome ("madam") -> true
Your Answer:
1 public boolean checkPalindrome(String s) {
2.
6 }
Transcribed Image Text:Code Workout X275: Recursion Programming Exercise: Check Palindrome Write a recursive function named checkPalindrome that takes a string as input, and returns true if the string is a palindrome and false if it is not a palindrome. A string is a palindrome if it reads the same forwards or backwards. Recall that str.charAt(a) will return the character at position a in str. str.substring(a) will return the substring of str from position a to the end of str,while str.substring(a, b) will return the substring of str starting at position a and continuing to (but not including) the character at position b. Examples: checkPalindrome ("madam") -> true Your Answer: 1 public boolean checkPalindrome(String s) { 2. 6 }
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