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(x2, y2) (х3, у3) (x2, y2) (x2, у2) (х3, у3) (х3, у3) (x4, y4) (xl, yl) (x4, y4) (x1, yl) (r4. y4) (b) (x1, yl) (a) (c)

(x2, y2) (х3, у3) (x2, y2) (x2, у2) (х3, у3) (х3, у3) (x4, y4) (xl, yl) (x4, y4) (x1, yl) (r4. y4) (b) (x1, yl) (a) (c)

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

Two points on line 1 are given as (x1, y1) and (x2,
y2) and on line 2 as (x3, y3) and (x4, y4), as shown in Figure 3.8a and b.
The intersecting point of the two lines can be found by solving the following linear
equations:
(y1 - y2)x - (x1 - x2)y = (y1 - y2)x1 - (x1 - x2)y1
(y3 - y4)x - (x3 - x4)y = (y3 - y4)x3 - (x3 - x4)y3
This linear equation can be solved using Cramer’s rule . If the equation has no solutions, the two lines are parallel (see Figure).

Write a program that prompts the user to enter four points and displays the intersecting
point. Here are sample runs:

(x2, y2) (х3, у3) (x2, y2) (x2, у2) (х3, у3) (х3, у3) (x4, y4) (xl, yl) (x4, y4) (x1, yl) (r4. y4) (b) (x1, yl) (a) (c)
Transcribed Image Text:(x2, y2) (х3, у3) (x2, y2) (x2, у2) (х3, у3) (х3, у3) (x4, y4) (xl, yl) (x4, y4) (x1, yl) (r4. y4) (b) (x1, yl) (a) (c)
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