x+2 x+2 12-4x+3 Find the quotient x2-5x +6 x+ 2 x# 1, x 3 -2

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter1: Equations And Inequalities
Section1.CR: Chapter Review
Problem 71E
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Question
**Finding the Quotient**

**Problem:**

Find the quotient \( \frac{\frac{x + 2}{x^2 - 5x + 6}}{\frac{x + 2}{x^2 - 4x + 3}} \).

**Choices:**

1. \( \frac{x + 2}{x - 1}, \, x \neq 1, \, x \neq 3 \)
2. \( \frac{x - 1}{x - 2}, \, x \neq 2 \)
3. \( \frac{x + 2}{x - 2}, \, x \neq -2, \, x \neq 2 \)
4. \( \frac{x - 1}{x - 2}, \, x \neq 1, \, x \neq 3 \)

**Explanation:**

To find the quotient of the given expressions, we need to divide the first fraction by the second fraction.

Given expressions:
\[ \frac{x + 2}{x^2 - 5x + 6} \]
\[ \frac{x + 2}{x^2 - 4x + 3} \]

Step 1: Factor the denominators.
\[ x^2 - 5x + 6 = (x - 2)(x - 3) \]
\[ x^2 - 4x + 3 = (x - 1)(x - 3) \]

Step 2: Rewrite the expression with the factored denominators.
\[ \frac{x + 2}{(x - 2)(x - 3)} \div \frac{x + 2}{(x - 1)(x - 3)} \]

Step 3: Perform the division by multiplying by the reciprocal.
\[ \frac{x + 2}{(x - 2)(x - 3)} \times \frac{(x - 1)(x - 3)}{x + 2} \]

Step 4: Simplify the expression by canceling common terms.
\[ \frac{(x + 2) \cdot (x - 1)(x - 3)}{(x - 2)(x - 3) \cdot (x + 2)} \]

Cancel common factors \(x + 2\) and \(x - 3\).
\[ \frac
Transcribed Image Text:**Finding the Quotient** **Problem:** Find the quotient \( \frac{\frac{x + 2}{x^2 - 5x + 6}}{\frac{x + 2}{x^2 - 4x + 3}} \). **Choices:** 1. \( \frac{x + 2}{x - 1}, \, x \neq 1, \, x \neq 3 \) 2. \( \frac{x - 1}{x - 2}, \, x \neq 2 \) 3. \( \frac{x + 2}{x - 2}, \, x \neq -2, \, x \neq 2 \) 4. \( \frac{x - 1}{x - 2}, \, x \neq 1, \, x \neq 3 \) **Explanation:** To find the quotient of the given expressions, we need to divide the first fraction by the second fraction. Given expressions: \[ \frac{x + 2}{x^2 - 5x + 6} \] \[ \frac{x + 2}{x^2 - 4x + 3} \] Step 1: Factor the denominators. \[ x^2 - 5x + 6 = (x - 2)(x - 3) \] \[ x^2 - 4x + 3 = (x - 1)(x - 3) \] Step 2: Rewrite the expression with the factored denominators. \[ \frac{x + 2}{(x - 2)(x - 3)} \div \frac{x + 2}{(x - 1)(x - 3)} \] Step 3: Perform the division by multiplying by the reciprocal. \[ \frac{x + 2}{(x - 2)(x - 3)} \times \frac{(x - 1)(x - 3)}{x + 2} \] Step 4: Simplify the expression by canceling common terms. \[ \frac{(x + 2) \cdot (x - 1)(x - 3)}{(x - 2)(x - 3) \cdot (x + 2)} \] Cancel common factors \(x + 2\) and \(x - 3\). \[ \frac
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