sinxIt can be shown that 1 –6.< 1, for x near 0.sinxEvaluate limO 1O undefinedO DNEO None of these choices2)

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Answered: x2 It can be shown that 1 – 6. sinx <…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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1 1 lim x-0 sin?x x2
sin2 Evaluate the following Iimit. 5(cosx-1) Im cinx Change the glven Indeterminate form Into a deteminate form. Choose the correct answer below. 5( cotx-1) O A. sin x O B. -5(1+ cos x) C. - (1+ + cos X) sin x OD. 5( cotx-1) Evaluate the limit. Select the correct cholce below and, if necessary, fll in the answer box to complete your cholce. 5( cos x- 1) O A. Im because each function is continuous for all x. (Simplify your answer.) OB. The limit does not exist and is neither oo nor - co.
Investigate the three special functions by performing the following task. Write ana comparison of your answer on the limits of any of the special functions after each item.
NO TE: When using interval notation in WeBWork, remember that: You use 'INF' for oo and '-INF' for -0o. And use 'U' for the union symbol. Enter DNE if an answer does not exist. f(x) = -2 sin(x) cos(z) on (-7, 7) a) Find the critical numbers of f. -pi/4, pi/4 (Separate multiple answers by commas.) b) Determine the intervals on which f is increasing and decreasing. f is increasing on: (pi/4.pi) f is decreasing on: (-pi/4.pi/4) c) Use the First Derivative Test to determine whether each critical point is a relative maximum, minimum, or neither. Relative maxima occur at x = -pl/4 (Separate multiple answers by commas.) Relative minima occur at x pi/4 (Separate multiple answers by commas.)
x* – 2x3 Find Lim x-0 x5 + 5x²° A. 00 В. - 4 С. D. 0 olo
evaluate

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x2 It can be shown that 1 – 6. sinx < 1, for x near 0. sinx Evaluate lim O 1 O undefined O DNE O None of these choices VI