x2 arctan x dx

Q: 2x-1 dx

A: Given,

Q: sec4 dx

A: The integral is . Let . Differentiating both sides.

Q: dx 24x

A: The given integral is  I1=∫dx24x Solving the integral  I1=∫dx24x=∫2-4xdxLet -4x=u⇒-4dx=du⇒I1=-14∫2u…

Q: 1. f4x-³ dx -3

A: Find the integral

Q: x* + 10x dx

A: Evaluate the given integral as follows. Let u = x + 5 and du = dx and simplify as follows.

Q: v5-x dx

A:

Q: x2 - 4 3 dx

A: The given integral is: I=∫x2-4x3dx

Q: dx XI. Vx(x+1)

A: Here I am attaching image so that you understand each and every step.

Q: secx dx

A:

Q: 3 dx x-2

A:

Q: 3. tan x dx

A: Formula: tan2x=sec2x-1

Q: | sech²xtanh²x dx

A: We can find the integration as below

Q: Stan 3x sec 3x dx 3.

A:

Q: tan³/3x secº/3x

A: Given that, ∫tan33xsec63xxdx

Q: dx 1 sin-xcot-x 2

A:

Q: 9 coshx - 5 sinhx 15 %3D

A: To solve  9coshx-5sinhx=15