x2 – 2x + 17 = 0 -6+ v – 4ac 2a -(-2) ± V(-2) – 4 (1) (17) 2 (1) x = 1+4i = (x - (1+4i)) (r - (1 – 41)) =(2 - (1+41)) (x - (1– 41)) 1士4i

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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i am not sure how the answer is being found
12 – 2x + 17 = 0
-6± vb2 – 4ac
2a
-(-2) + V(-2) – 4 (1) (17)
2 (1)
x = 1+ 4i
f (2) = (x - (1+ 4i)) (r – (1 – 4i))
f (2) = (2 - (1+ 4i)) (* – (1 – 4i))
1+4i
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Transcribed Image Text:12 – 2x + 17 = 0 -6± vb2 – 4ac 2a -(-2) + V(-2) – 4 (1) (17) 2 (1) x = 1+ 4i f (2) = (x - (1+ 4i)) (r – (1 – 4i)) f (2) = (2 - (1+ 4i)) (* – (1 – 4i)) 1+4i Sponsored by Connecticut Tourism Explore Parks Kids Will Love Take the kids on a summer adventure! Check out these CT Stat
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