x2 – 10x – 14 = -3? O (x – 5)² = –14 O (x – 5)2 = 36 O (x + 5)² = 36 O (x + 5)? = –14 |

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Topic Video
Question
x2 – 10x – 14 = –3?
O (x – 5)² = –14
O ( – 5)² = 36
O (x + 5)² = 36
O (x + 5)² = –14
Transcribed Image Text:x2 – 10x – 14 = –3? O (x – 5)² = –14 O ( – 5)² = 36 O (x + 5)² = 36 O (x + 5)² = –14
Expert Solution
Step 1

x² - 10x - 14 = - 3

So, x² - 10x = 14 - 3

So, x² - 10x = 11

So, (x² - 2•x•5 + 5²) = 11 + 5²

So, (x - 5)² = 36

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