(x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z < N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hello

Continuing with this problem, shown in the picture, where the  parameterization for S was determined, how do i now calculate the area. Could you help set up the integral for this equation? 

(x, y, z) = (cos z, sin z, z), − < z <
Explanation:
Step 1:
y = x tan(z)
with:
x>0, x²+ y² = 1
−√ < ± < √
Step 2:
sin(z)
y = x cos(2)
Step 3:
substitute y:
x²+x2. sin².
cos2
Then we get:
=
2 . (cos's+sin= 2)
Hence we would get:
x² = cos² z
Step 4:
Since
x0, cos z> 0
We would get:
x = COS z
1
sin(z)
y = cos z.
== sin z
cos(2)
Hence the parametric form is:
(x, y, z) = (cos z, sin z, z), — √ <≤ z <
Transcribed Image Text:(x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z <
N
# 2
1.5
1
y
0.5
++
+
2
1.5
1
0.5
425
-0.5
-1
-1.5
-2
0.5
1
15
-2
Transcribed Image Text:N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2
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