(x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z < N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2
(x, y, z) = (cos z, sin z, z), − < z < Explanation: Step 1: y = x tan(z) with: x>0, x²+ y² = 1 −√ < ± < √ Step 2: sin(z) y = x cos(2) Step 3: substitute y: x²+x2. sin². cos2 Then we get: = 2 . (cos's+sin= 2) Hence we would get: x² = cos² z Step 4: Since x0, cos z> 0 We would get: x = COS z 1 sin(z) y = cos z. == sin z cos(2) Hence the parametric form is: (x, y, z) = (cos z, sin z, z), — √ <≤ z < N # 2 1.5 1 y 0.5 ++ + 2 1.5 1 0.5 425 -0.5 -1 -1.5 -2 0.5 1 15 -2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Continuing with this problem, shown in the picture, where the parameterization for S was determined, how do i now calculate the area. Could you help set up the integral for this equation?
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