(x) (x) How?! (x) (x) = (2x+3) (x) = (x+3) रे (2x+3) २ २ - D (2x+3) [₁ + [+] 2x+3 २ _2x +5 २ 1 +.. [-() (): of (@x +9) + D (2x+3) D? -0 + 1 - 0 +1

Q: y=(2e+1) (x+2)* y= ?

A:

Q: (3x-1)2/x+1

A:

Q: 2+(29-xy)

A: We first get rid of the bracket.  So,  2+(29-xy)=2+29-xy

Q: 65. (x + 3)(x - 3)(4x2 - 9)

A: Given: Let p=x+3x-34x2-9 To Find: To evaluate the given expression.

Q: Given f(x) = 7x and g(x) = 7x^2+9a. (f of g)(4) b. (g of f)(2) c. (f of f)(1) d. ( g of g)(0)

A: To evaluate the composite functions at given points

Q: 5(1-x)=6(1+2x)+5  What does the x equal

A:

Q: (fof-¹)(x) = 26² 3x 2 -44x+1 2 3(3x² + 4x +) 2 )-1 44

A:

Q: 7(3x+6)=11-(x+2)

A: Given an algebraic equation. We shall solve the equation for x.

Q: 2(x+3)=5(x+1)

A:

Q: ((x-1/4y-1)-3)/ (x5/4y0)

A:

Q: 6x + 8y = 3 (a) 3x – 10y = 5

A:

Q: P(x)= x^3 — 9x^2+ 11x+ 21; -1 The other zeros are x=

A:

Q: A(x)=x3-7x2-16x+112,(x-7)

A: Given:     Ax=x3-7x2-16x+112 , x-7   Divide the leading term of the dividend by the leading term of…

Q: (q/q-3) + 1 = (2/2q+1)

A: To solve for q, firstly, we take l.c.m on left hand side of equation.

Q: (x)/(x+4)+(7)/(x-1)= 2

A: Given query is to find the solution of the expression.

Q: 2(3-x)=3(1-x)=

A: Given equation: 23-x=31-x 2×(3-x)=3×(1-x)2×3-2×x=3×1-3×x6-2x=3-3x

Q: If C(x) = 9x² - 8, find the following. (a) C(0) (b) c(-1) (c) C(-3) (d) ((--)

A:

Q: 2x-x xp - (r-1)° (x²+1) -0-

A: Given ∫-∞0 2x-x3x-12x2+1 dx                         =-∫-∞0x3-2xx-12x2+1dx…

Q: [(*+4) - 8]* dx 32 (*+ 4 )3

A: The given integral is 32∫0∞x+4-82x+43dx. Evaluate the value of given integral.

Q: X=6{2+3[2(8-3)+(4+1)-2]}

A: Given,          x=62+328-3+4+1-2

Q: 4(x+4)=3+4x

A: The given equation is

Q: (x) = - 4x2 + 2

A: We will find out the required values.

Q: Let r(x) = 8x - 5 7x +9 x) = (-5x-5)/(7x-8) Find and simplify

A: Given query is to find inverse t.

Q: ×ャ3 4x2_8x+3 2.) x2+3x -4ノ 2x3 + Sx? -1x+6

A:

Q: 4(x+5)=3(x-4)+x

A: Given,

Q: (x+9)/8 = 5/4 +(x-3)/2

A: To calculate the value of x from the provided equation which is shown below,