(x =t² +2t ly=t* -2t For the parameter equation the equation of the tangent to the graph of the curve at (3, –1) is а. Зу-х%3D-6 b. 2y – x = - 5 c. 2y + x = 1 d. y-2x = -7 е. y +2x =5 a O b O c d

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