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X-ray radiation falls in the wavelend 1.00×10" to 1.00 x 10°8 meters. What is the energy of x-ray radiat has a wavelength of 1.00×10 -// Energy - Ins/photon

X-ray radiation falls in the wavelend 1.00×10" to 1.00 x 10°8 meters. What is the energy of x-ray radiat has a wavelength of 1.00×10 -// Energy - Ins/photon

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**X-ray Radiation and Energy Calculation** X-ray radiation falls in the wavelength range of \(1.00 \times 10^{-11}\) to \(1.00 \times 10^{-8}\) meters. **Problem:** What is the energy of X-ray radiation that has a wavelength of \(1.00 \times 10^{-11}\) meters? **Solution:** Calculate the energy using the formula: \[ \text{Energy} = \frac{hc}{\lambda} \] Where: - \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)) - \(c\) is the speed of light (\(3.00 \times 10^{8} \, \text{m/s}\)) - \(\lambda\) is the wavelength Plug in the values: \[ \text{Energy} = \frac{(6.626 \times 10^{-34} \, \text{Js})(3.00 \times 10^{8} \, \text{m/s})}{1.00 \times 10^{-11} \, \text{m}} \] Calculate to find the energy in Joules, and convert to kilojoules per photon if needed. \[ \text{Energy} = \, \text{___ kJ/photon} \]
Transcribed Image Text:**X-ray Radiation and Energy Calculation** X-ray radiation falls in the wavelength range of \(1.00 \times 10^{-11}\) to \(1.00 \times 10^{-8}\) meters. **Problem:** What is the energy of X-ray radiation that has a wavelength of \(1.00 \times 10^{-11}\) meters? **Solution:** Calculate the energy using the formula: \[ \text{Energy} = \frac{hc}{\lambda} \] Where: - \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)) - \(c\) is the speed of light (\(3.00 \times 10^{8} \, \text{m/s}\)) - \(\lambda\) is the wavelength Plug in the values: \[ \text{Energy} = \frac{(6.626 \times 10^{-34} \, \text{Js})(3.00 \times 10^{8} \, \text{m/s})}{1.00 \times 10^{-11} \, \text{m}} \] Calculate to find the energy in Joules, and convert to kilojoules per photon if needed. \[ \text{Energy} = \, \text{___ kJ/photon} \]
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