X - products plot of In[ X ] vs. time -0.2 -0.4 -0.6 y = -0.2967x-0.1621 -0.8 -1.2 -1.4 -1.6 -1.8 time / minutes [X] was measured over time, and the plot shown above was constructed from that data. The plot is linear (R² = 0.999), with the slope = -0.2967. .... If this reaction has a constant “half-life", what is the half-life ? minutes [x ]u

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### Reaction Kinetics: Understanding the Decomposition of X

#### Reaction Overview:
\[ X \rightarrow \text{products} \]

#### Data Analysis:
A time-dependent measurement of the concentration of \( [X] \) was conducted. The corresponding data was used to create the linear plot as shown below.

#### Graph Description:
**Title:** plot of ln([X]) vs. time  
**X-axis:** time / minutes (ranging from 0 to 6)  
**Y-axis:** ln([X]) (values ranging from -1.8 to -0.2)  
**Line Equation:** \( y = -0.2967x - 0.1621 \)

The plot is linear, characterized by a high correlation coefficient of \( R^2 = 0.999 \), indicating a strong linear relationship between the natural logarithm of the concentration of \( [X] \) and time. The slope of the line is -0.2967.

![Graph of ln([X]) vs. time](#)
- **X-axis (time / minutes):** The horizontal axis represents the time in minutes, with equally spaced intervals.
- **Y-axis (ln([X])):** The vertical axis denotes the natural logarithm of the concentration of \( [X] \).
- **Trendline and Equation:** A trendline is plotted to show the linear relationship between the ln([X]) and time, with the equation \( y = -0.2967x - 0.1621 \).

#### Calculation of Reaction Half-Life:
The half-life of a reaction can be determined from the slope of the linear plot.

**Question:**

If this reaction has a constant "half-life", what is the half-life?

\[ \text{Half-life} = \_\_\_\_\_\_\_\_\_\_ \text{ minutes} \]

### Further Instructions:
To derive the half-life from the slope of the plot above, use the following formula:
\[ t_{1/2} = \frac{\ln(2)}{-\text{slope}} \]

Apply this to find the specific half-life time for the reaction depicted.

---

For further discussion and detailed step-by-step solutions, please refer to the relevant sections in your course materials or reach out to your instructor.
Transcribed Image Text:### Reaction Kinetics: Understanding the Decomposition of X #### Reaction Overview: \[ X \rightarrow \text{products} \] #### Data Analysis: A time-dependent measurement of the concentration of \( [X] \) was conducted. The corresponding data was used to create the linear plot as shown below. #### Graph Description: **Title:** plot of ln([X]) vs. time **X-axis:** time / minutes (ranging from 0 to 6) **Y-axis:** ln([X]) (values ranging from -1.8 to -0.2) **Line Equation:** \( y = -0.2967x - 0.1621 \) The plot is linear, characterized by a high correlation coefficient of \( R^2 = 0.999 \), indicating a strong linear relationship between the natural logarithm of the concentration of \( [X] \) and time. The slope of the line is -0.2967. ![Graph of ln([X]) vs. time](#) - **X-axis (time / minutes):** The horizontal axis represents the time in minutes, with equally spaced intervals. - **Y-axis (ln([X])):** The vertical axis denotes the natural logarithm of the concentration of \( [X] \). - **Trendline and Equation:** A trendline is plotted to show the linear relationship between the ln([X]) and time, with the equation \( y = -0.2967x - 0.1621 \). #### Calculation of Reaction Half-Life: The half-life of a reaction can be determined from the slope of the linear plot. **Question:** If this reaction has a constant "half-life", what is the half-life? \[ \text{Half-life} = \_\_\_\_\_\_\_\_\_\_ \text{ minutes} \] ### Further Instructions: To derive the half-life from the slope of the plot above, use the following formula: \[ t_{1/2} = \frac{\ln(2)}{-\text{slope}} \] Apply this to find the specific half-life time for the reaction depicted. --- For further discussion and detailed step-by-step solutions, please refer to the relevant sections in your course materials or reach out to your instructor.
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