X is normally distributed random variable with a mean of 60 and standard deviation of 8. Find the probabilities indicated by using the standard normal table. 1. P(X < 52) 2. P(48 < X < 64) 3. P(X >
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- you should calculate the required probabilities using tables A model for normal human body temperature, X, when measured orally in F, is that it is normally distributed, X N(98.2, 0.5184). According to the model that you just derived for W, what proportion of people have a normal body temperature of between 36 °C and 36.8 C? ()you should calculate the required probabilities using tables A model for normal human body temperature, X, when measured orally in F, is that it is normally distributed, X N(98.2, 0.5184). According to the model, what proportion of people have a normal body temperature of 99 F or more? (0) (i) Find the normal body temperature such that, according to the model, only 10% of people have a lower normal body temperature. (ii) Let W denote normal human body temperature, when measured orally in C. Given that W =59 (X-32) and X N(98.2, 0.5184), what is the distribution of W?ty
- Applying the Normal Distribution and Central Limit Theorem The population of adult women in the United States has a mean height of 65 inches (5'5") and a standard deviation of 3.5 inches. Let X = the height of an American female. Thus, X~ N(65, 3.5). Use the scenario above to determine the selected probabilities below. You may wish to use the Normal Distribution Calculator hosted by the University of lowa's Department of Mathematical Sciences. Remember: the formatting of this calculator may vary slightly from what is used in class. (link: Normal Distribution Calculator) a. What is the probability of randomly selecting a female shorter than 58 inches tall? P(X<58) = (Include five decimal places.) b. Determine the 90th percentile for the distribution. (This Normal Distribution Percentile Calculator may be useful.) x = inches. (Include one decimal place.) c. If 100 women were randomly chosen, what is the probability that the sample mean of this group would be less than 64.5 inches? P(X <…The absolute tolerance is +-0.01Weekly salaries of college students in a large city are normally distributed with a mean of 650 dollars and a standard deviation of 65 dollars.Find the probability that a randomly selected weekly salary in this distribution is less than 605 dollars. P(X < 605) =
- Suppose tht the duration of a particular type of criminal trial is known to have a mean of 24 days and a standard deviation of 8 days. We randomly sample 9 trials. Part (b) Given the distribution of Σx Σx~ N ( ____ , ____) Part (C) Find the probability that the total length of the 9 trials is at least 249 days. (Round your answer to four decimals places) Part (D) Seventy percent of the total of 9 of these types of trials will last at least how long? (Round your answer to two decimal places)A random number generator picks a number from 6 to 65 in a uniform manner. Round answers to 4 decimal places when possible. The mean of this distribution is . The standard deviation is . The probability that the number will be exactly 48 is P(x=48)=P(x=48)= . The probability that the number will be between 17 and 22 is P(17<x<22)=P(17<x<22)= . The probability that the number will be larger than 50 is P(x>50)=P(x>50)= . P(x>24∣x<57)=P(x>24∣x<57)= . Find the 21st percentile. Find the minimum for the upper quarter.You are playing a card came, and the probability that you will win a game is p = 0.73. If you play the game 1412 times, what is the most likely number of wins? (Round answer to one decimal place.) Let X represent the number of games (out of 1412) that you win. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) O = The range rule of thumb specifies that the minimum usual value for a random variable is u-2o and the maximum usual value is p+2o. You already found u and o for the random variable X. Use the range rule of thumb to find the usual range of X values. Enter answer as an interval using square- brackets and only whole numbers. usual values =
- engineering statistics.prpobability***Only do this question if using Minitab and show images*** Let X1, X2, X3, . . . , X200 denote the weights of 200 independent and identically distributed bags of candy corn. If the mean weight of each bag is 2 lb. and its standard deviation is 0.07 lb., determine the probability that the average of 200 bags weighs between 1.997 lb. and 2.06 lb. Show your answer using Minitab.Random variable has a normal distribution w/ mean = 25 & variance = 2.25 Determine the following probabilities: • P (20 < X < 28) • P (X < 27)