{x ER: 2x + 31+x=0} = {-6, -2}
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Discrete mathematics. Need help prove that
![The expression depicted in the image is an equation involving absolute values:
\[
\{ x \in \mathbb{R}: 2|x + 3| + x = 0 \} = \{-6, -2\}
\]
Explanation:
- This equation defines the set of real numbers \( x \) such that \( 2|x + 3| + x = 0 \).
- The solution to this equation is the set \(\{-6, -2\}\), meaning that \( x = -6 \) and \( x = -2 \) satisfy the equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3d40ab3-26fa-4cc6-a20f-30a7f32ffb5d%2F320348a8-fa29-4e20-99bf-55bee4ae53ea%2Fmdz3owd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The expression depicted in the image is an equation involving absolute values:
\[
\{ x \in \mathbb{R}: 2|x + 3| + x = 0 \} = \{-6, -2\}
\]
Explanation:
- This equation defines the set of real numbers \( x \) such that \( 2|x + 3| + x = 0 \).
- The solution to this equation is the set \(\{-6, -2\}\), meaning that \( x = -6 \) and \( x = -2 \) satisfy the equation.
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Step 1: Expand the mod function
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