{x e C([0, 1]) : x(0) = 0} with the sup norm and x(t) dt = 0. 5-8 (a) Let X = Y X: Then Y is a closed proper subspace of X. But there is no r1 E X with |a1|lo = 1 and dist(x1, Y) = 1. (Compare 5.3.) (b) Let Y be a finite dimensional proper subspace of a normed space X. Then there is some r E X with ||a|| 1 and dist(r, Y) 1. (Compare 5.3.) %3D
{x e C([0, 1]) : x(0) = 0} with the sup norm and x(t) dt = 0. 5-8 (a) Let X = Y X: Then Y is a closed proper subspace of X. But there is no r1 E X with |a1|lo = 1 and dist(x1, Y) = 1. (Compare 5.3.) (b) Let Y be a finite dimensional proper subspace of a normed space X. Then there is some r E X with ||a|| 1 and dist(r, Y) 1. (Compare 5.3.) %3D
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter3: Matrices
Section3.5: Subspaces, Basis, Dimension, And Rank
Problem 10EQ
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![5-8
(a) Let X = {x € C([0, 1]) : (0) = 0} with the sup norm and
3D{=EX:/ x(t) dt = 0. Then Y is a closed proper subspace of X.
But there is no r1 € X with ||x1|lo = 1 and dist(x1, Y) = 1. (Compare
Y:
%3D
5.3.)
(b) Let Y be a finite dimensional proper subspace of a normed space
X. Then there is some r E X with ||a|| 1 and dist(r, Y) = 1. (Compare
%3D
5.3.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4bba3fcc-01db-410a-a86c-d766584e6d07%2F944d7fac-d6bc-4e0d-94f0-f85306b36c84%2F0aohzzj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5-8
(a) Let X = {x € C([0, 1]) : (0) = 0} with the sup norm and
3D{=EX:/ x(t) dt = 0. Then Y is a closed proper subspace of X.
But there is no r1 € X with ||x1|lo = 1 and dist(x1, Y) = 1. (Compare
Y:
%3D
5.3.)
(b) Let Y be a finite dimensional proper subspace of a normed space
X. Then there is some r E X with ||a|| 1 and dist(r, Y) = 1. (Compare
%3D
5.3.)
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