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x" dx = x2 +1 ( x"-2(x2 +1 – 1) x² + 1 67. (а) 1, dx = x*-2 dx = п — 1 - In-2 - x2 + 1 (b) lo = tan-lx+C; I1 = } In (x² +1} + C; I2 = x – tan-lx+ C; I3 = - } In (x² + 1) + C; I4 = – x + tan-lx + C; Is =-+In (x² + 1) + C (c) Prove by induction; show it works for n = 1, then assume it works for n = k and use that to show it works for n = k + 1. - x + tan-x + C;

x" dx = x2 +1 ( x"-2(x2 +1 – 1) x² + 1 67. (а) 1, dx = x*-2 dx = п — 1 - In-2 - x2 + 1 (b) lo = tan-lx+C; I1 = } In (x² +1} + C; I2 = x – tan-lx+ C; I3 = - } In (x² + 1) + C; I4 = – x + tan-lx + C; Is =-+In (x² + 1) + C (c) Prove by induction; show it works for n = 1, then assume it works for n = k and use that to show it works for n = k + 1. - x + tan-x + C;

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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x" dx = x2 +1 ( x"-2(x2 +1 – 1) x² + 1 67. (а) 1, dx = x*-2 dx = п — 1 - In-2 - x2 + 1 (b) lo = tan-lx+C; I1 = } In (x² +1} + C; I2 = x – tan-lx+ C; I3 = - } In (x² + 1) + C; I4 = – x + tan-lx + C; Is =-+In (x² + 1) + C (c) Prove by induction; show it works for n = 1, then assume it works for n = k and use that to show it works for n = k + 1. - x + tan-x + C;
Transcribed Image Text:x" dx = x2 +1 ( x"-2(x2 +1 – 1) x² + 1 67. (а) 1, dx = x*-2 dx = п — 1 - In-2 - x2 + 1 (b) lo = tan-lx+C; I1 = } In (x² +1} + C; I2 = x – tan-lx+ C; I3 = - } In (x² + 1) + C; I4 = – x + tan-lx + C; Is =-+In (x² + 1) + C (c) Prove by induction; show it works for n = 1, then assume it works for n = k and use that to show it works for n = k + 1. - x + tan-x + C;
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