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x B × x b x х х х

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Several electrons move at speed 5.00 × 10^5 m/s in a uniform magnetic field with magnitude B = 0.500 T directed downward. Find the magnetic force on the electron at point c where the velocity of the electron maks a 30 deg angle with the horizontal, pointing to the upper right. Enter a positive value if the direction of magnetic force is out of the page and enter a negative value if the direction of magnetic force is in to the page. Use E-scientific notation. Round to 2 decimal places.
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A hexagonal loop of side L = 7.1 cm carries a current of I = 1.6 A (see figure below). Determine the magnetic field at the center of the loop. Assume the positive z axis points out of the page. (Express your answer in vector form.) B = T
A triangle loop of wire (length of each side is 5 cm and the angle between legs is 600) hangs vertically as shown in Fig.6. A magnetic field B is directed horizontally, perpendicular to the wire, and points out of the page at all points and passes through half of the triangle. The loop hangs from a balance which measures a downward magnetic force (in addition to the gravitational force) of F = 5.0 x 10-2 N when the wire carries a current I = 0.5 A. What is the magnitude of the magnetic field B?
A loop in the form of an equilateral triangle with side L is in the first quadrant of the xy plane with one of the vertices at the origin and one of the sides on the x axis. Obtain the magnetic force on each side of the triangle if a current I passes through the loop and the applied magnetic field is given by Bo = (Box)i + (Bo)k, with Bo> 0. What is the total force on the loop? Obs: the magnetic field it's not defined in j.
After being accelerated to a speed of 1.92×105 m/s , the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 34.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb.
The net force on a current loop in a uniform magnetic field is zero. But what if B is not uniform? The figure (Figure 1) shows a square loop of wire that lies in the xy-plane. The loop has corners at (0, 0), (0, L), (L, 0), and (L, L) and carries a constant current I in the clockwise direction. The magnetic field has no x-component but has both y- and z- components: B = (Boz/L)j + (Boy/L) k, where Bo is a positive constant. Figure y (0, L) (0, 0) (L, L) (L, 0) 1 of 1 X Part E Find the magnitude of the force on side 3, that runs from (L, L) to (L, 0). Express your answer in terms of the variables Bo, L, and I. — ΑΣΦ F3 = Submit Part F Request Answer Find the direction of the force on side 1, that runs from (L, L) to (L, 0). +x-direction -x-direction +y-direction -y-direction +z-direction -z-direction 0 Submit ? Request Answer
Diamagnets have the property that they "dampen" the effects of an external magnetic field by creating an opposing magnetic field. The diamagnet thus has an induced dipole moment that is anti- aligned, such that the induced north pole is closer to the north pole creating the external field. An application of this is that diamagnets can be levitated 2. Now, the mathematics of generally describing a force by a non-uniform field on a dipole is a little beyond the scope of this course, but we can still work through an approximation based on energy. Essentially, whenever the theoretical loss of gravitational potential energy from "falling" no longer can "pay the cost" of increasing the magnetic potential energy, the object no longer wants to fall. Suppose a diamagnetic object floats above the levitator where the magnitude of the magnetic field is 12 T, which is inducing" a magnetic dipole moment of 4.6 LA - m² in the object. The magnetic field 1.9 mm below the object is stronger with a…
Consider the two current-carrying wires in the figure. On the left is a long, straight wire carrying current I. In the same plane, there is a rectangular loop, which carries a current I2. The dimensions of the rectangular loop are shown in the figure, and the left side of the loop is a distance c from the wire. What are the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire? (Use any variable or symbol stated above along with the following as necessary: Ho, l, and a.) magnitude F = direction ---Select--
Consider the system pictured in the figure below. A 15.7-cm horizontal wire of mass 15.1 g is placed between two thin, vertical conductors, and a uniform magnetic field acts perpendicular to the page. The wire is free to move vertically without friction on the two vertical conductors. When a 5.20-A current is directed as shown in the figure, the horizontal wire moves upward at constant velocity in the presence of gravity. (a) What forces act on the horizontal wire? (Select all that apply.) O electric force O gravitational force O magnetic force (b) Under what condition is the wire able to move upward at constant velocity? (c) Find the magnitude and direction of the minimum magnetic field required to move the wire at constant speed. magnitude direction ---Select--- (d) What happens if the magnetic field exceeds this minimum value?
The net force on a current loop in a uniform magnetic field is zero. But what if B is not uniform? The figure (Figure 1) shows a square loop of wire that lies in the xy-plane. The loop has corners at (0, 0), (0, L), (L, 0), and (L, L) and carries a constant current I in the clockwise direction. The magnetic field has no x-component but has both y- and z- components: B = (Boz/L) j+ (Boy/L) Ê, where Bo is a positive constant. Figure (0, L) y (0, 0) (L, L) (L, 0) 1 of 1 X Part I Find the magnitude of the net magnetic force on the loop. Express your answer in terms of the variables Bo, L, and I. WG | ΑΣΦ F = Submit Part J O Find the direction of the net magnetic force on the loop. O O O Request Answer +x-direction -x-direction +y-direction -y-direction +z-direction -z-direction 0 Submit Request Answer X Roarson ?