Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![This image illustrates the process of polynomial long division. The given expression is divided by \(x - 1\). The long division involves the following steps:
1. **Division Set-Up**:
- Dividend: \(x^3 + 3x^2 - 2x + 6\)
- Divisor: \(x - 1\)
2. **First Step**:
- Divide the first term of the dividend (\(x^3\)) by the first term of the divisor (\(x\)) to get \(x^2\).
- Multiply \(x^2\) by the divisor \(x - 1\), which gives \(x^3 - x^2\).
- Subtract \(x^3 - x^2\) from the dividend to get a new dividend of \(4x^2 - 2x\).
3. **Second Step**:
- Divide the first term of the new dividend (\(4x^2\)) by the first term of the divisor (\(x\)) to get \(4x\).
- Multiply \(4x\) by the divisor \(x - 1\), which gives \(4x^2 - 4x\).
- Subtract \(4x^2 - 4x\) from the current dividend to get a new dividend of \(2x + 6\).
4. **Third Step**:
- Divide the first term of the new dividend (\(2x\)) by the first term of the divisor (\(x\)) to get \(2\).
- Multiply \(2\) by the divisor \(x - 1\), which gives \(2x - 2\).
- Subtract \(2x - 2\) from the current dividend to get the remainder \(8\).
5. **Result**:
- The quotient is \(x^2 + 4x + 2\).
- The remainder is \(8\).
The final expression is:
\[ x^2 + 4x + 2 + \frac{8}{x-1} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2574792-c8b9-4dbb-8bcc-60e76e59b591%2F09f648df-bd8d-4a21-b932-7cc46d46898c%2Ftef38x_processed.png&w=3840&q=75)
Transcribed Image Text:This image illustrates the process of polynomial long division. The given expression is divided by \(x - 1\). The long division involves the following steps:
1. **Division Set-Up**:
- Dividend: \(x^3 + 3x^2 - 2x + 6\)
- Divisor: \(x - 1\)
2. **First Step**:
- Divide the first term of the dividend (\(x^3\)) by the first term of the divisor (\(x\)) to get \(x^2\).
- Multiply \(x^2\) by the divisor \(x - 1\), which gives \(x^3 - x^2\).
- Subtract \(x^3 - x^2\) from the dividend to get a new dividend of \(4x^2 - 2x\).
3. **Second Step**:
- Divide the first term of the new dividend (\(4x^2\)) by the first term of the divisor (\(x\)) to get \(4x\).
- Multiply \(4x\) by the divisor \(x - 1\), which gives \(4x^2 - 4x\).
- Subtract \(4x^2 - 4x\) from the current dividend to get a new dividend of \(2x + 6\).
4. **Third Step**:
- Divide the first term of the new dividend (\(2x\)) by the first term of the divisor (\(x\)) to get \(2\).
- Multiply \(2\) by the divisor \(x - 1\), which gives \(2x - 2\).
- Subtract \(2x - 2\) from the current dividend to get the remainder \(8\).
5. **Result**:
- The quotient is \(x^2 + 4x + 2\).
- The remainder is \(8\).
The final expression is:
\[ x^2 + 4x + 2 + \frac{8}{x-1} \]
![**Mathematics Problem: Polynomial Division**
**Problem Statement:**
Divide \( 9x^2 + 6x \) by \( 3x \). Show or explain how you got your answer.
**Solution Explanation:**
To divide the polynomial \( 9x^2 + 6x \) by \( 3x \), follow these steps:
1. **Divide Each Term:**
- **First Term:**
\[
\frac{9x^2}{3x} = 3x
\]
- **Second Term:**
\[
\frac{6x}{3x} = 2
\]
2. **Combine the Results:**
- The division yields:
\[
3x + 2
\]
Therefore, the result of dividing \( 9x^2 + 6x \) by \( 3x \) is \( 3x + 2 \).
**Conclusion:**
The division simplifies the polynomial to \( 3x + 2 \). The division process involves simplifying each term independently and then combining the simplified terms to get the final result.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2574792-c8b9-4dbb-8bcc-60e76e59b591%2F09f648df-bd8d-4a21-b932-7cc46d46898c%2Fmb9ekt9_processed.png&w=3840&q=75)
Transcribed Image Text:**Mathematics Problem: Polynomial Division**
**Problem Statement:**
Divide \( 9x^2 + 6x \) by \( 3x \). Show or explain how you got your answer.
**Solution Explanation:**
To divide the polynomial \( 9x^2 + 6x \) by \( 3x \), follow these steps:
1. **Divide Each Term:**
- **First Term:**
\[
\frac{9x^2}{3x} = 3x
\]
- **Second Term:**
\[
\frac{6x}{3x} = 2
\]
2. **Combine the Results:**
- The division yields:
\[
3x + 2
\]
Therefore, the result of dividing \( 9x^2 + 6x \) by \( 3x \) is \( 3x + 2 \).
**Conclusion:**
The division simplifies the polynomial to \( 3x + 2 \). The division process involves simplifying each term independently and then combining the simplified terms to get the final result.
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