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X+ダ-34=t (1) → (2) リ+X+2X - 2 =e Xcn =し XC1) = 0,ye) =-2 c) xC1) = 0 / yC) --2 ,c) :c→た

X+ダ-34=t (1) → (2) リ+X+2X - 2 =e Xcn =し XC1) = 0,ye) =-2 c) xC1) = 0 / yC) --2 ,c) :c→た

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please help me to solve the system of ODE's ((question 4)) in the below of page 4.
I attached an explanation with the question 3 for your help
Thank you.
[ Math. modeling ]

3/23 New system of 1St order ODE'S: X, = X2 C1) X2=2X2+3X1+3y-(2) ý = X2 +2 X1+L →) +5ý +Xy² = t° %3D 3 → (2) - Ic's Solu. let X2=X |X3= X aid Xs =Y X2=X Xs =7 Xy = Xs Inibial Condiblns Ic's Eqeil: x +5ý + Xy²=63 Ly = - 5ý -xy²+t³ 2. X(0)=1 X3 = -5 Xs - X, Xý +t3 Eq cz): ý -3X2 -2y =c X3(o)=6| -3X2 glo) = 10 Xs = 3 X3X4+2 Xy Xs col=1]
Transcribed Image Text:3/23 New system of 1St order ODE'S: X, = X2 C1) X2=2X2+3X1+3y-(2) ý = X2 +2 X1+L →) +5ý +Xy² = t° %3D 3 → (2) - Ic's Solu. let X2=X |X3= X aid Xs =Y X2=X Xs =7 Xy = Xs Inibial Condiblns Ic's Eqeil: x +5ý + Xy²=63 Ly = - 5ý -xy²+t³ 2. X(0)=1 X3 = -5 Xs - X, Xý +t3 Eq cz): ý -3X2 -2y =c X3(o)=6| -3X2 glo) = 10 Xs = 3 X3X4+2 Xy Xs col=1]
New system of ODE's : X = X2. A (1) X2= X3 A (2) X3= -5X5-X Xy +t3c Xy = X5 (4) Xs = 3X3 Xy + 2 Xy (5) Xi C0) =1, X2C01=0, X3(0) - 6, Xyl01=10, ts cu)=1['s の(メダー3y=t → (2) Ý +X +2X - 3y = é X () =!, X(I) = 0, yel =-2, ýCI) = c Miw. for you
Transcribed Image Text:New system of ODE's : X = X2. A (1) X2= X3 A (2) X3= -5X5-X Xy +t3c Xy = X5 (4) Xs = 3X3 Xy + 2 Xy (5) Xi C0) =1, X2C01=0, X3(0) - 6, Xyl01=10, ts cu)=1['s の(メダー3y=t → (2) Ý +X +2X - 3y = é X () =!, X(I) = 0, yel =-2, ýCI) = c Miw. for you
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