(x +3)3 4(x – 1)2 12 16 Consider the function f(x) 11 Note that (x – 1)2 4 1 - - (x – 9)(x+ 3)² 24(r + 3) f'(x) = and f"(x) = 4(x – 1)3 (r – 1)ª Use the Mean Value Theorem to show that the equation f'(x) = 0.01 has a solution in the interval (-4,-3)
(x +3)3 4(x – 1)2 12 16 Consider the function f(x) 11 Note that (x – 1)2 4 1 - - (x – 9)(x+ 3)² 24(r + 3) f'(x) = and f"(x) = 4(x – 1)3 (r – 1)ª Use the Mean Value Theorem to show that the equation f'(x) = 0.01 has a solution in the interval (-4,-3)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![(x + 3)3
4(x – 1)2
12
16
Consider the function f(x)
Note that
4
-1
(x – 1)2
(x – 9)(x + 3)²
4(x – 1)3
24(x + 3)
f'(x) =
and f"(x) =
(r – 1)4 *
-
Use the Mean Value Theorem to show that the equation f'(x) = 0.01 has a
solution in the interval (-4,-3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d32dc14-2c84-49d7-a6bc-c62d80442ef5%2F6c221bf8-f8ad-455b-a61b-0425e3f79e66%2Fghzxil_processed.png&w=3840&q=75)
Transcribed Image Text:(x + 3)3
4(x – 1)2
12
16
Consider the function f(x)
Note that
4
-1
(x – 1)2
(x – 9)(x + 3)²
4(x – 1)3
24(x + 3)
f'(x) =
and f"(x) =
(r – 1)4 *
-
Use the Mean Value Theorem to show that the equation f'(x) = 0.01 has a
solution in the interval (-4,-3)
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