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Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Find X
### Example Problem: Finding the Length of the Side in a Right-Angled Triangle

**Problem:**

You are given a right-angled triangle with one angle measuring 32 degrees. The side adjacent to this angle is labeled as "15" units long. The side opposite to the 32-degree angle is represented by "x". Your task is to find the value of \(x\).

**Diagram:**

A right-angled triangle is depicted. The triangle includes:
- An angle marked as 32°.
- The side adjacent to the 32° angle is labeled as 15 units.
- The side opposite to the 32° angle is labeled as \(x\).
- The hypotenuse is indicated by the right-angle symbol but is not labeled with a value.

**Steps to Solve:**

1. **Identify the trigonometric function to use**: 
    Since you have the adjacent side and need to find the opposite side, you can use the tangent function.
    
    \[
    \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
    \]

2. **Substitute the known values**:
    \[
    \tan(32^\circ) = \frac{x}{15}
    \]

3. **Solve for \(x\)**:
    \[
    x = 15 \times \tan(32^\circ)
    \]

4. **Calculate the value**:
    Using a calculator to find \(\tan(32^\circ)\):

    \[
    \tan(32^\circ) \approx 0.6249
    \]

    Therefore,

    \[
    x \approx 15 \times 0.6249 = 9.37
    \]

**Answer**:
The length of the side opposite the 32-degree angle is approximately 9.37 units.
Transcribed Image Text:### Example Problem: Finding the Length of the Side in a Right-Angled Triangle **Problem:** You are given a right-angled triangle with one angle measuring 32 degrees. The side adjacent to this angle is labeled as "15" units long. The side opposite to the 32-degree angle is represented by "x". Your task is to find the value of \(x\). **Diagram:** A right-angled triangle is depicted. The triangle includes: - An angle marked as 32°. - The side adjacent to the 32° angle is labeled as 15 units. - The side opposite to the 32° angle is labeled as \(x\). - The hypotenuse is indicated by the right-angle symbol but is not labeled with a value. **Steps to Solve:** 1. **Identify the trigonometric function to use**: Since you have the adjacent side and need to find the opposite side, you can use the tangent function. \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \] 2. **Substitute the known values**: \[ \tan(32^\circ) = \frac{x}{15} \] 3. **Solve for \(x\)**: \[ x = 15 \times \tan(32^\circ) \] 4. **Calculate the value**: Using a calculator to find \(\tan(32^\circ)\): \[ \tan(32^\circ) \approx 0.6249 \] Therefore, \[ x \approx 15 \times 0.6249 = 9.37 \] **Answer**: The length of the side opposite the 32-degree angle is approximately 9.37 units.
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