Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![**Problem Statement:**
Find the equation of the normal line to the parabola \( y = x^2 + 2x - 3 \) that is also parallel to \( -2x + 2y = 9 \).
**Solution Attempt:**
\[ y = x + \frac{15}{4} \]
**Feedback:**
The given solution is incorrect, as marked by the red cross.
---
**Explanation:**
This problem involves finding the equation of a normal line to a given parabola that is parallel to a specific line equation.
1. **Understanding the Parabola:**
- The parabola equation is \( y = x^2 + 2x - 3 \).
- The derivative, \( \frac{dy}{dx} = 2x + 2 \), gives the slope of the tangent at any point on the parabola.
2. **Normal Line Slope:**
- The slope of the normal line is the negative reciprocal of the tangent slope.
3. **Parallel Line Condition:**
- Line \( -2x + 2y = 9 \) can be rearranged to standard form: \( y = x + \frac{9}{2} \).
- The slope is 1. So, the normal line must parallel a line with slope 1, meaning its slope is the same.
4. **Conclusion:**
- The attempted solution did not correctly align with these criteria.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff094594d-f83b-4542-841d-d67d95a5e494%2Fbf12600a-b5c2-4fc3-b13e-640f0b3c64ed%2Fgefexhb_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Find the equation of the normal line to the parabola \( y = x^2 + 2x - 3 \) that is also parallel to \( -2x + 2y = 9 \).
**Solution Attempt:**
\[ y = x + \frac{15}{4} \]
**Feedback:**
The given solution is incorrect, as marked by the red cross.
---
**Explanation:**
This problem involves finding the equation of a normal line to a given parabola that is parallel to a specific line equation.
1. **Understanding the Parabola:**
- The parabola equation is \( y = x^2 + 2x - 3 \).
- The derivative, \( \frac{dy}{dx} = 2x + 2 \), gives the slope of the tangent at any point on the parabola.
2. **Normal Line Slope:**
- The slope of the normal line is the negative reciprocal of the tangent slope.
3. **Parallel Line Condition:**
- Line \( -2x + 2y = 9 \) can be rearranged to standard form: \( y = x + \frac{9}{2} \).
- The slope is 1. So, the normal line must parallel a line with slope 1, meaning its slope is the same.
4. **Conclusion:**
- The attempted solution did not correctly align with these criteria.
Expert Solution

Step 1
Definition used -
Slope of normal - The slope of normal at a point is the negative reciprocal of the slope of the tangent at that point.
The slope of normal for function f(x) at x = a can be found by the given formula -
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Solved in 4 steps

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