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x = 2 (mod 5) 2r = 22 (mod 8) 3x = 12 (mod 21) (i) How many solutions does it have lying between 0 and 1679?

x = 2 (mod 5) 2r = 22 (mod 8) 3x = 12 (mod 21) (i) How many solutions does it have lying between 0 and 1679?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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x = 2 (mod 5) 22 (mod 8) 2r = 3.x = 12 (mod 21) (i) How many solutions does it have lying between 0 and 1679?
Transcribed Image Text:x = 2 (mod 5) 22 (mod 8) 2r = 3.x = 12 (mod 21) (i) How many solutions does it have lying between 0 and 1679?
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