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(x + 16)*24x dx =

(x + 16)*24x dx =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 1 When evaluating Integrals of the form tutx))"u'x) de- du, (n -1), we use an extension of the Powers of x Formula. This formula is called the Power Rule for Integration. + C, (n -1) n+1 Therefore, any Integrand that we can rewrite as the product of a power of a function of x times the derivative of that function can be integrated using this formula. Notice that the Integrand, (8x + 16)*(24x), includes a power of u(x) - Bx+ 16. Let u- + 16, then du = 8 + 16 dx. Thus, we can use the Power Rule for Integration with the power n -4 Submit Skin (you cannot.come.back)
Transcribed Image Text:Step 1 When evaluating Integrals of the form tutx))"u'x) de- du, (n -1), we use an extension of the Powers of x Formula. This formula is called the Power Rule for Integration. + C, (n -1) n+1 Therefore, any Integrand that we can rewrite as the product of a power of a function of x times the derivative of that function can be integrated using this formula. Notice that the Integrand, (8x + 16)*(24x), includes a power of u(x) - Bx+ 16. Let u- + 16, then du = 8 + 16 dx. Thus, we can use the Power Rule for Integration with the power n -4 Submit Skin (you cannot.come.back)
Finally, substitute u 8x + 16 to determine the integral in terms of x. Use C for the constant of integration. 24x + 16 5 (8x + 16)*24x dx = +C
Transcribed Image Text:Finally, substitute u 8x + 16 to determine the integral in terms of x. Use C for the constant of integration. 24x + 16 5 (8x + 16)*24x dx = +C
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