x = 16 – y? (v = 16) 4 x = y? – 4 (u = -4) 3 R x = 9 - v2 (v = 9) x= y? (u = 0) + 8 2 4 6 u =x- y? v =x + y? X = (u + v)/2 y = V(v – u/2 v 16 12 Figure 16.82 2.
x = 16 – y? (v = 16) 4 x = y? – 4 (u = -4) 3 R x = 9 - v2 (v = 9) x= y? (u = 0) + 8 2 4 6 u =x- y? v =x + y? X = (u + v)/2 y = V(v – u/2 v 16 12 Figure 16.82 2.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Change of variables determined by the region Let R be the region
in the first quadrant bounded by the parabolas x = y2, x = y2 - 4, x = 9 - y2, and x = 16 - y2 (see image). Evaluate ∫∫R y2 dA.
![x = 16 – y?
(v = 16)
4
x = y? – 4
(u = -4)
3
R
x = 9 - v2
(v = 9)
x= y?
(u = 0)
+
8
2
4
6
u =x- y?
v =x + y?
X = (u + v)/2
y = V(v – u/2
v
16
12
Figure 16.82
2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9f6be946-9050-4750-8aee-6b82f51679e3%2F088b23eb-8483-4ac5-bed3-75a0ef49338e%2F95xt64r.png&w=3840&q=75)
Transcribed Image Text:x = 16 – y?
(v = 16)
4
x = y? – 4
(u = -4)
3
R
x = 9 - v2
(v = 9)
x= y?
(u = 0)
+
8
2
4
6
u =x- y?
v =x + y?
X = (u + v)/2
y = V(v – u/2
v
16
12
Figure 16.82
2.
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