(x²-1) y"- 6x y¹+12y=0 where prime denotes the derivative with respect to x. Assume a solution of the form y= c¸xn. n=0 Also assume that the following initial conditions are given y (0) =1, and y'(0) =2. Choose All Correct Answers Below B F G x = 1 is an ordinary point. H The recurrence relation is given by: This equation has no singular points. x = -1 is a singular point. Ex=0 is an ordinary point. (n-3)(n-4) n+2¯¯ (n+1)(n+2) n A particular solution is given by y=x²-2x³ + 6x² - 2x + 1 The recurrence relation is given by: (n-2)(n-3) (n+2)(n+3) , n=0,1,2,... A particular solution is given by y=x²+2x³ + 6x² + 2x + 1 с 11 , n=0,1,2,...

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the differential equation
(x²-1) y"- 6x y¹+12y=0
where prime denotes the derivative with respect to x.
Assume a solution of the form y=
Σcx².
n=0
Also assume that the following initial conditions are given y (0) =1, and y'(0) =2.
Choose All Correct Answers Below
(A x = 1 is an ordinary point.
(В
E
F
(G)
The recurrence relation is given by:
(H)
C
n+2
Dx= -1 is a singular point.
=
(n-3) (n-4)
C
(n+1) (n+2) n
This equation has no singular points.
x = 0 is an ordinary point.
A particular solution is given by
y = x² − 2x³ + 6x² − 2x + 1
The recurrence relation is given by:
с
n+2
=
(n-2)(n-3)
(n+ 2)(n+3)
.
A particular solution is given by
y = x² + 2x³ + 6x² + 2x + 1
C
n
n = 0,1,2,...
.
n=0,1,2,...
Transcribed Image Text:Consider the differential equation (x²-1) y"- 6x y¹+12y=0 where prime denotes the derivative with respect to x. Assume a solution of the form y= Σcx². n=0 Also assume that the following initial conditions are given y (0) =1, and y'(0) =2. Choose All Correct Answers Below (A x = 1 is an ordinary point. (В E F (G) The recurrence relation is given by: (H) C n+2 Dx= -1 is a singular point. = (n-3) (n-4) C (n+1) (n+2) n This equation has no singular points. x = 0 is an ordinary point. A particular solution is given by y = x² − 2x³ + 6x² − 2x + 1 The recurrence relation is given by: с n+2 = (n-2)(n-3) (n+ 2)(n+3) . A particular solution is given by y = x² + 2x³ + 6x² + 2x + 1 C n n = 0,1,2,... . n=0,1,2,...
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