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x + 1 2. To solve the nonlinear inequality < 0, we first observe *- 2 are zeros of the numerator that the numbers. and. and denominator. These numbers divide the real line into three intervals. Complete the table. Interval Sign of x + 1 Sign of x Sign of (x + 1)/(x - 2) Do any of the endpoints fail to satisfy the inequality? If so, which one(s)? The solution of the inequality is

x + 1 2. To solve the nonlinear inequality < 0, we first observe *- 2 are zeros of the numerator that the numbers. and. and denominator. These numbers divide the real line into three intervals. Complete the table. Interval Sign of x + 1 Sign of x Sign of (x + 1)/(x - 2) Do any of the endpoints fail to satisfy the inequality? If so, which one(s)? The solution of the inequality is

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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x + 1 2. To solve the nonlinear inequality < 0, we first observe *- 2 are zeros of the numerator that the numbers. and. and denominator. These numbers divide the real line into three intervals. Complete the table. Interval Sign of x + 1 Sign of x Sign of (x + 1)/(x - 2) Do any of the endpoints fail to satisfy the inequality? If so, which one(s)? The solution of the inequality is
Transcribed Image Text:x + 1 2. To solve the nonlinear inequality < 0, we first observe *- 2 are zeros of the numerator that the numbers. and. and denominator. These numbers divide the real line into three intervals. Complete the table. Interval Sign of x + 1 Sign of x Sign of (x + 1)/(x - 2) Do any of the endpoints fail to satisfy the inequality? If so, which one(s)? The solution of the inequality is
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