X -1 1 0 3 1/8 Setting M = max(X,Y), thus the distribution table of Mis ( 1 4. The probability distribution table of (X,Y) is Y 4 M P₁ M P₁ M P -1 1/8 -1 1/8 M P₁ 1 3/8 3/8 0 0 3/8 OK 1/8 1 3/4 2 3/8 1 3/8 1 5/8 3 1/4 1 3/8 0 3 1/4 3 1/8 2 1/8 2 0 1/8 2
X -1 1 0 3 1/8 Setting M = max(X,Y), thus the distribution table of Mis ( 1 4. The probability distribution table of (X,Y) is Y 4 M P₁ M P₁ M P -1 1/8 -1 1/8 M P₁ 1 3/8 3/8 0 0 3/8 OK 1/8 1 3/4 2 3/8 1 3/8 1 5/8 3 1/4 1 3/8 0 3 1/4 3 1/8 2 1/8 2 0 1/8 2
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![4. The probability distribution table of (X,Y) is
-1
0
1
0
3/8
3
1/8
0
Setting M = max{X,Y), thus the distribution table of Mis (
)
X
(4)
(2)
Y
M
P₁
M
P₁
M
P₁
-1
1/8
-1
1/8
M
P₁
1
3/8
0
3/8
0
1/8
1
3/4
2
3/8
1
3/8
1
5/8
3
1/4
1
3/8
0
3
1/4
3
1/8
2
1/8
2
0
1/8
2
||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0a0eb44-0d82-4149-bd9e-63330869cded%2F76112a7c-1fbb-4068-9bee-33c8f69b6c5c%2Fhb10bv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. The probability distribution table of (X,Y) is
-1
0
1
0
3/8
3
1/8
0
Setting M = max{X,Y), thus the distribution table of Mis (
)
X
(4)
(2)
Y
M
P₁
M
P₁
M
P₁
-1
1/8
-1
1/8
M
P₁
1
3/8
0
3/8
0
1/8
1
3/4
2
3/8
1
3/8
1
5/8
3
1/4
1
3/8
0
3
1/4
3
1/8
2
1/8
2
0
1/8
2
||
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