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X -1 1 0 3 1/8 Setting M = max(X,Y), thus the distribution table of Mis ( 1 4. The probability distribution table of (X,Y) is Y 4 M P₁ M P₁ M P -1 1/8 -1 1/8 M P₁ 1 3/8 3/8 0 0 3/8 OK 1/8 1 3/4 2 3/8 1 3/8 1 5/8 3 1/4 1 3/8 0 3 1/4 3 1/8 2 1/8 2 0 1/8 2

X -1 1 0 3 1/8 Setting M = max(X,Y), thus the distribution table of Mis ( 1 4. The probability distribution table of (X,Y) is Y 4 M P₁ M P₁ M P -1 1/8 -1 1/8 M P₁ 1 3/8 3/8 0 0 3/8 OK 1/8 1 3/4 2 3/8 1 3/8 1 5/8 3 1/4 1 3/8 0 3 1/4 3 1/8 2 1/8 2 0 1/8 2

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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4. The probability distribution table of (X,Y) is -1 0 1 0 3/8 3 1/8 0 Setting M = max{X,Y), thus the distribution table of Mis ( ) X (4) (2) Y M P₁ M P₁ M P₁ -1 1/8 -1 1/8 M P₁ 1 3/8 0 3/8 0 1/8 1 3/4 2 3/8 1 3/8 1 5/8 3 1/4 1 3/8 0 3 1/4 3 1/8 2 1/8 2 0 1/8 2 ||
Transcribed Image Text:4. The probability distribution table of (X,Y) is -1 0 1 0 3/8 3 1/8 0 Setting M = max{X,Y), thus the distribution table of Mis ( ) X (4) (2) Y M P₁ M P₁ M P₁ -1 1/8 -1 1/8 M P₁ 1 3/8 0 3/8 0 1/8 1 3/4 2 3/8 1 3/8 1 5/8 3 1/4 1 3/8 0 3 1/4 3 1/8 2 1/8 2 0 1/8 2 ||
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