X / 0° V O a. -19.34 + j-5.72 V O b.-37.31 + j-5.72 V O c.-19.34 + j-27.46 V O d. 21.54 +j-38.77 V O e. 1.45 + j-84.92 V O f. -1244.00 + j-33.54 V 40 Ω www O g. 17.66 + j-21.23 V O h. 1136.00 + j-56.60 V j20 Ω m y/0° A V : -j30 ΩΣ 50 Ω Question 1) Since the amplitude value of the above circuit de voltage source is x=68V and the amplitude value of the current source is y=2A calculate the value of the V node voltage. Question 1) The amplitude of the voltage source is x=68V and the amplitude of the current source is y=2A, then find the node voltage V in the above circuit. –
X / 0° V O a. -19.34 + j-5.72 V O b.-37.31 + j-5.72 V O c.-19.34 + j-27.46 V O d. 21.54 +j-38.77 V O e. 1.45 + j-84.92 V O f. -1244.00 + j-33.54 V 40 Ω www O g. 17.66 + j-21.23 V O h. 1136.00 + j-56.60 V j20 Ω m y/0° A V : -j30 ΩΣ 50 Ω Question 1) Since the amplitude value of the above circuit de voltage source is x=68V and the amplitude value of the current source is y=2A calculate the value of the V node voltage. Question 1) The amplitude of the voltage source is x=68V and the amplitude of the current source is y=2A, then find the node voltage V in the above circuit. –
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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KVL and KCL
KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.
Sign Convention
Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.
Question
Circuit theory
Transcribed Image Text:X / 0° V
O a. -19.34 + j-5.72 V
O b. -37.31 + j-5.72 V
O c. -19.34 + j-27.46 V
O d. 21.54 + j-38.77 V
O e. 1.45 + j-84.92 V
O f.-1244.00 + j-33.54 V
40 Ω
j20 Ω
wwwm
O g. 17.66 + j-21.23 V
O h. 1136.00 + j-56.60 V
y/0° A
V
– –j30 Ω
www
Question 1) Since the amplitude value of the above circuit de voltage source is x=68V and the amplitude value of the current source is y=2A calculate the value of the V
node voltage.
Question 1) The amplitude of the voltage source is x=68V and the amplitude of the current source is y=2A, then find the node voltage V in the above circuit.
50 Ω
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