please solve it v,(t) =Vm sin(wt)Figure 1. A single-phase full-wave rectifier with an RL-source load. Figure 1 shows a single-phase full-wave rectifier with an RL-source load. (a) Provide an expression of the output voltage v, asa Fourier series consisting of a de term and the even harmonics whose frequencies are multiples of 2w (two times the supplyfrequency) for the continuous current mode; that is, the output current i, > 0 at all times for steady-state operation. (b) Derivean expression of i, for the continuous current mode (Hint: Use superposition). (c) Calculate the power absorbed by the devoltage source and the power absorbed by the load resistor for the ac source amplitude Vm = v2 · 120 V, the ac source angularfrequency w = 2n60 rad/s, R = 2 0, L = 10 mH, and Vae= 80 V for the continuous current operation and considering the determ and the first two harmonics (the second and fourth harmonics) in the Fourier series.

Given data, Vm=1202R=2 ΩL=10 mHVdc=80 V

Answered: ww ell v,(t) = Vm sin(wt) 本

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Electrical Engineering

ww ell v,(t) = Vm sin(wt) 本

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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please solve it

v,(t) =
Vm sin(wt)
Figure 1. A single-phase full-wave rectifier with an RL-source load.

Figure 1 shows a single-phase full-wave rectifier with an RL-source load. (a) Provide an expression of the output voltage v, as
a Fourier series consisting of a de term and the even harmonics whose frequencies are multiples of 2w (two times the supply
frequency) for the continuous current mode; that is, the output current i, > 0 at all times for steady-state operation. (b) Derive
an expression of i, for the continuous current mode (Hint: Use superposition). (c) Calculate the power absorbed by the de
voltage source and the power absorbed by the load resistor for the ac source amplitude Vm = v2 · 120 V, the ac source angular
frequency w = 2n60 rad/s, R = 2 0, L = 10 mH, and Vae= 80 V for the continuous current operation and considering the de
term and the first two harmonics (the second and fourth harmonics) in the Fourier series.

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