Writing a program in C++ that combines the three summations and linear search algorithm together in one code and there will be an improvement in the three summation algorithm performance? three summations 3-sum: brute-force algorithm Linear Search Algorithm publie elass Threaßun • The linear search algorithm locates an item in a list by examining elements in the sequence one at a time, starting at the beginning. • First compare x with a,. If they are equal, return the position 1. • If not, try a,, If x a, return the position 2. • Keep going, and if no match is found when the entire list is scanned, publie statie int count (int() a) int N-.length: int eount- 0: for (int i- 0: i
Writing a program in C++ that combines the three summations and linear search algorithm together in one code and there will be an improvement in the three summation algorithm performance? three summations 3-sum: brute-force algorithm Linear Search Algorithm publie elass Threaßun • The linear search algorithm locates an item in a list by examining elements in the sequence one at a time, starting at the beginning. • First compare x with a,. If they are equal, return the position 1. • If not, try a,, If x a, return the position 2. • Keep going, and if no match is found when the entire list is scanned, publie statie int count (int() a) int N-.length: int eount- 0: for (int i- 0: i
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
![Writing a program in C++ that combines the three summations and linear search algorithm
together in one code and there will be an improvement in the three summation algorithm
performance?
three summations
3-sum: brute-force algorithm
Linear Search Algorithm
publie elass Threesun
• The linear search algorithm locates an item in a list by examining elements in
the sequence one at a time, starting at the beginning.
• First compare x with a,. If they are equal, return the position 1.
• If not, try a,, If x = a, return the position 2.
• Keep going, and if no match is found when the entire list is scanned,
publie statie int count (int(] a)
int N-a.length:
int count- o:
for (int i- 0; i<N; 1++)
for (int j = 1+1: 3< N; ++)
for (int k- j+1; k< N; k++)
if (a(4) + al1 + a[k] - 0)
return 0.
check each triple
procedure linear search(x:integer,
a, a, ..a: distinct integers)
for simplicity, ignore
count++:
integer overflow
return count;
i:-1
while (isn and x + a)
public static void nain (String() args)
i:=i+1
ifisn then location := i
else location := 0
return location{location is the subscript of the term that
equals x, or is 0 if x is not found}
int() a- In. readints (arga (0]):
Stdout.printin (count (a) ):](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ee020aa-5e74-4bff-ba2c-b0f93e8cf3af%2Fb6d325c3-6614-409f-befb-d39fd1791c37%2Fu5sqoon_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Writing a program in C++ that combines the three summations and linear search algorithm
together in one code and there will be an improvement in the three summation algorithm
performance?
three summations
3-sum: brute-force algorithm
Linear Search Algorithm
publie elass Threesun
• The linear search algorithm locates an item in a list by examining elements in
the sequence one at a time, starting at the beginning.
• First compare x with a,. If they are equal, return the position 1.
• If not, try a,, If x = a, return the position 2.
• Keep going, and if no match is found when the entire list is scanned,
publie statie int count (int(] a)
int N-a.length:
int count- o:
for (int i- 0; i<N; 1++)
for (int j = 1+1: 3< N; ++)
for (int k- j+1; k< N; k++)
if (a(4) + al1 + a[k] - 0)
return 0.
check each triple
procedure linear search(x:integer,
a, a, ..a: distinct integers)
for simplicity, ignore
count++:
integer overflow
return count;
i:-1
while (isn and x + a)
public static void nain (String() args)
i:=i+1
ifisn then location := i
else location := 0
return location{location is the subscript of the term that
equals x, or is 0 if x is not found}
int() a- In. readints (arga (0]):
Stdout.printin (count (a) ):
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