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Write the standard form of the equation of the line that is perpendicular to the graph of the given equation and that passes through the point with the given coordinates... 10. 2x-y+6= 0; (0, -3) 11. 2x - 5y-6=0; (-4, 2) 12. 3x+4y - 13 = 0; (2,7)

Write the standard form of the equation of the line that is perpendicular to the graph of the given equation and that passes through the point with the given coordinates... 10. 2x-y+6= 0; (0, -3) 11. 2x - 5y-6=0; (-4, 2) 12. 3x+4y - 13 = 0; (2,7)

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.4: Writing And Graphing Equations Of Lines
Problem 80E
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Write the standard form of the equation of the line that is perpendicular to the graph of the given equation and that passes through the point with the given coordinates... 10. 2x -y + 6 = 0; (0, -3) 11. 2x-5y-6=0; (-4, 2) 12. 3x +4-13= 0; (2, 7)
Transcribed Image Text:Write the standard form of the equation of the line that is perpendicular to the graph of the given equation and that passes through the point with the given coordinates... 10. 2x -y + 6 = 0; (0, -3) 11. 2x-5y-6=0; (-4, 2) 12. 3x +4-13= 0; (2, 7)
Expert Solution
Given

The given equation and points,

10. 2x-y+6=0 , 0,-311. 2x-5y-6=0, -4,212. 3x+4y-13=0, 2,7

The equation of line is of the form y=mx+c

where, m is the slope of the line

Perpendicular lines:

   If two lines are perpendicular then product of their slopes equal to -1

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Follow-up Question

Where did -12 for the slope and one half for the other slop for #10 come from?

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