Write the standard form of the equation of the circle with the graph shown to the right. What is the standard form of the equation of the circle to the right?

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter8: Introduction To Functions
Section8.2: Points, Lines, And Their Graphs
Problem 24OE
Question
**Geometry Lesson 12.5.17: Finding the Standard Form of a Circle's Equation**

**Objective:**
Write the standard form of the equation of the circle using the given graph.

**Problem Statement:**
"Write the standard form of the equation of the circle with the graph shown to the right. What is the standard form of the equation of the circle to the right?"

**Graph Analysis:**
The graph provided displays a circle plotted on a coordinate plane. The circle’s center appears to be at the coordinate point \((3, -5)\) and its radius seems to be 2 units, based on the grid.

**Solution:**
The standard form of a circle’s equation is:

\[ (x - h)^2 + (y - k)^2 = r^2 \]

where \((h, k)\) is the center of the circle and \(r\) is the radius.

From the graph: 
- Center \((h, k) = (3, -5)\)
- Radius \(r = 2\)

Plugging these values into the standard form equation:

\[ (x - 3)^2 + (y + 5)^2 = 2^2 \]
\[ (x - 3)^2 + (y + 5)^2 = 4 \]

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Transcribed Image Text:**Geometry Lesson 12.5.17: Finding the Standard Form of a Circle's Equation** **Objective:** Write the standard form of the equation of the circle using the given graph. **Problem Statement:** "Write the standard form of the equation of the circle with the graph shown to the right. What is the standard form of the equation of the circle to the right?" **Graph Analysis:** The graph provided displays a circle plotted on a coordinate plane. The circle’s center appears to be at the coordinate point \((3, -5)\) and its radius seems to be 2 units, based on the grid. **Solution:** The standard form of a circle’s equation is: \[ (x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center of the circle and \(r\) is the radius. From the graph: - Center \((h, k) = (3, -5)\) - Radius \(r = 2\) Plugging these values into the standard form equation: \[ (x - 3)^2 + (y + 5)^2 = 2^2 \] \[ (x - 3)^2 + (y + 5)^2 = 4 \] **Interactive Component:** *Enter your answer in the box below and click "Check Answer."* [Input Box] [Check Answer Button] **Note:** All parts showing. [Clear All Button]
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